How to assign the size of a k-th column of a cell to the k+1-th?

Hi everybody,

I need to assign the size of the k-th column of a cell to the k+1-th in a for loop. This form seems not to work because the index exceeds the number of array elements (1).

sbc{k}=size(cycles{k+1});

[Mathieu NOE]

hello

can you post the entire code ?

[Rik]

Your text seems to suggest the indices should be the other way around.

[Flavia Lerra]

I would like that the size of the k-th column is equal to the k+1-th one.

for k = 1:N
    myfilename = sprintf('file_#%d.xlsx', k);
    mydata{k} = xlsread(myfilename);
    
    cycles{k}= mydata{k}(:,5);
    
    sbc{k}=size(cycles{k+1});
end

[Rik]

And what value should the last element of sbc have?

[Flavia Lerra]

sbc should be the size of the k+1-th column

Answer 1

[Rik]

When you execute this line:

sbc{k}=size(cycles{k+1})

the k+1 element of cycles doesn't exist yet. You will have to make sure your loop starts 1 later and does sbc{k-1}.

Alternatively you can use a second loop that runs up N-1.