Clear Filters
Clear Filters

how to find the angle subtended from origin to the poles in complex plane?

10 views (last 30 days)
clc
clear all
s=tf('s');
num=1;
den=(s+(-65+65j))*(s-(65+65j));
sys=num/den;
pzmap(sys)
i want to find the angle subtended by these poles from origin?

Accepted Answer

David Goodmanson
David Goodmanson on 17 Oct 2021
Edited: David Goodmanson on 17 Oct 2021
Hello Muhammed,
it's as easy as
angle(65+65j)
angle(65-65j)
with each angle in radians subtended from the x axis, -pi < angle <= pi

More Answers (0)

Categories

Find more on Change Markers in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!