Find roots of a first order differential equation

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Hello
I have a created a function in matlab:
function [fx] = Function(x, r)
fx = r - 2*cos(x);
end
Now I would like to find the zero points of the function for r = 1 and x between - 2pi and 2pi.
Thank you!

Accepted Answer

Star Strider
Star Strider on 21 Oct 2021
Try this —
r = 1;
x = linspace(-2*pi, 2*pi, 25);
y = Function(x,r);
zxidx = find(diff(sign(y))); % Indices Of Approximate Zero-Crossings
for k = 1:numel(zxidx)
x0(k) = fzero(@(x)Function(x,r),x(zxidx(k)));
end
x0(:)
ans = 4×1
-5.2360 -1.0472 1.0472 5.2360
figure
plot(x, y, '-b', x0,zeros(size(x0)),'or')
grid
function [fx] = Function(x, r)
fx = r - 2*cos(x);
end
.

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R2021a

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