creating array with specific condition

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data= 689 x 1
% moving average values for the last 50 data
data_average(1)= mean(data(1));
data_average(2)= mean(data(1:2));
data_average(50)= mean(data(1:50));
.
data_average(51)= mean(data(2:51));
data_average(52)= mean(data(3:52));
.
data_average(689)=mean(data(640:689));
How I can vectorize this computation?

Accepted Answer

Walter Roberson
Walter Roberson on 28 Dec 2021
data_average = movmean(data, [49, 0]);

More Answers (1)

sermet OGUTCU
sermet OGUTCU on 29 Dec 2021
Dear Walter, thank you very much for the solution.

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