read file containing mixed content

1 view (last 30 days)
b
b on 8 Jan 2022
Commented: b on 12 Jan 2022
Hello,
The format of an input text file is the following:
1 23.08 был
2 367.92 сказал
3 12567.53 когда
...
and so on.
How to read this file so that the following loop can be used:
for i=1:length(file)
str=fileName(i,3);
...
end
Thanks.
  9 Comments
b
b on 12 Jan 2022
Thank you. Thats exactly where the problem was.

Sign in to comment.

Accepted Answer

Image Analyst
Image Analyst on 8 Jan 2022
Try this:
% Get file name
fullFileName = fullfile(pwd, 'a.txt')
if ~isfile(fullFileName)
errorMessage = sprintf('Error: file not found:\n%s', fullFileName);
fprintf('%s\n', errorMessage)
uiwait(errordlg(errorMessage))
return;
end
% Open the file for reading in text mode.
fileID = fopen(fullFileName, 'rt');
% Read the first line of the file.
textLine = fgetl(fileID);
lineCounter = 1;
while ischar(textLine)
% Print out what line we're operating on.
fprintf('%s\n', textLine);
% Split into words.
words = strsplit(textLine);
% Assign to vectors
col1(lineCounter) = str2double(words{1});
col2(lineCounter) = str2double(words{2});
col3{lineCounter} = words{3};
% Read the next line.
textLine = fgetl(fileID);
lineCounter = lineCounter + 1;
end
% All done reading all lines, so close the file.
fclose(fileID);
% Transpose from row vectors into column vectors
col1 = col1'
col2 = col2'
col3 = col3'
  3 Comments
b
b on 10 Jan 2022
Hmmm ... oddly and strangely, it is somehow working now ...

Sign in to comment.

More Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!