I have a system of ODE equations. In the function file when I had to define Zero Array, I get an error for matrix array. How can I fix it?

1 view (last 30 days)
clc;
clear;
close all;
global k1 k2 k3 k4 Cp Re k We De MuR delt n bta yii www
Cp=0.5;
Re=.5;
We=.2;
De=1;
k1=10;
k2=1;
k3=.5;
k4=1;
delt=2;
bta=0.37;
k=1.4;
n=180;
a=zeros(n,1); b=zeros(n,1); a(1)=1; b(1)=1;
for k=2:n, a(k)=2*(k-1)+1; b(k)=(k-1)^2; end
JacM=diag(a)+diag(sqrt(b(2:n)),1)+diag(sqrt(b(2:n)),-1);
[w,x]=eig(JacM); x=diag(x); w=w(1,:)'.^2;
yii=x; www=w;
MuRi=[0.1];
np=numel(MuRi);
figure(1);
COLORS=hsv(np);
for i=1:np
MuR=MuRi(i);
options = odeset('RelTol',1e-9,'AbsTol',1e-9,'MaxStep',1e-9);
iniMat=[1,0,ones(1,n)];
[time,Y] = ode15s(@FthixoPrf,[0 80],iniMat);
subplot(2,1,1);
plot(time,Y(:,1),'Color',COLORS(i,:),'DisplayName',['MuR = ' num2str(MuR)]);
hold on;
subplot(2,1,2);
plot(time,Y(:,3),'Color',COLORS(i,:));
hold on;
end
grid on;
unction file:
function dy=FthixoPrf(t,y)
global k1 k2 k3 k4 Cp Re k We De MuR delt n bta yii www
dy = zeros(n,n);
R=y(1);U=y(2);
Str=y(3:n+2);
gamRR=y(n+3:2*n+2);
gamTT=y(2*n+3:3*n+2)
dy(1)=U;
sum=0;
for i=1:n
s1=www(i)*exp(yii(i))*(MuR+Str(i))/(yii(i)+R^3)^2;
s2=www(i)*exp(yii(i))*Str(i)*(gamRR(i)-gamTT(i))/(yii(i)+R^3);
sum=(-4*R*U*s1/Re)+(2*s2/(3*Re*De*R));
end
dy(2)=(-1.5*U^2+Cp*((1+We)*(1/R)^(3*k)-We/R-(1+delt*sin(t))))/R+sum;
for i=1:n
epsi=abs(2*sqrt(3)*R^2*U/(R^3+yii(i)));
dy(2+i)=(1/(t+0.0001)^bta)*(-k1*Str(i)*epsi+k2*(epsi)^0.5*(1-Str(i))+k3*(1-Str(i)));
inv2sqrt=(k2*(epsi)^0.5*+k3)/(k1*epsi+k2*(epsi)^0.5+k3);
dy(n+2+i)=(k4^bta/(t+0.0001)^bta)*(MuR+inv2sqrt)*gamRR(i)*(4*R^2*U/(R^3+yii(i)));
dy(2*n+2+i)=-(k4^bta/(t+0.0001)^bta)*(MuR+inv2sqrt)*gamTT(i)*(2*R^2*U/(R^3+yii(i)));
end
end

Answers (1)

Torsten
Torsten on 27 Mar 2022
dy = zeros(3*n+2,1)
But then you also have to specify 3*n+2 initial values for the variables you solve for.
You only specify n+2.
  7 Comments
Torsten
Torsten on 27 Mar 2022
I don't know your initial conditions. I just changed them to
iniMat=[1;0;ones(3*n,1)];
and in the function
dy = zeros(3*n+2,1);
and the code is syntactically correct.
global k1 k2 k3 k4 Cp Re k We De MuR delt n bta yii www
Cp=0.5;
Re=.5;
We=.2;
De=1;
k1=10;
k2=1;
k3=.5;
k4=1;
delt=2;
bta=0.37;
k=1.4;
n=180;
a=zeros(n,1); b=zeros(n,1); a(1)=1; b(1)=1;
for k=2:n, a(k)=2*(k-1)+1; b(k)=(k-1)^2; end
JacM=diag(a)+diag(sqrt(b(2:n)),1)+diag(sqrt(b(2:n)),-1);
[w,x]=eig(JacM); x=diag(x); w=w(1,:)'.^2;
yii=x; www=w;
MuRi=[0.1];
np=numel(MuRi);
figure(1);
COLORS=hsv(np);
for i=1:np
MuR=MuRi(i);
options = odeset('RelTol',1e-9,'AbsTol',1e-9,'MaxStep',1e-9);
iniMat=[1;0;ones(3*n,1)];
[time,Y] = ode15s(@FthixoPrf,[0 80],iniMat);
subplot(2,1,1);
plot(time,Y(:,1),'Color',COLORS(i,:),'DisplayName',['MuR = ' num2str(MuR)]);
hold on;
subplot(2,1,2);
plot(time,Y(:,3),'Color',COLORS(i,:));
hold on;
end
grid on
function dy=FthixoPrf(t,y)
global k1 k2 k3 k4 Cp Re k We De MuR delt n bta yii www
t
dy = zeros(3*n+2,1);
R=y(1);U=y(2);
Str=y(3:n+2);
gamRR=y(n+3:2*n+2);
gamTT=y(2*n+3:3*n+2);
dy(1)=U;
sum=0;
for i=1:n
s1=www(i)*exp(yii(i))*(MuR+Str(i))/(yii(i)+R^3)^2;
s2=www(i)*exp(yii(i))*Str(i)*(gamRR(i)-gamTT(i))/(yii(i)+R^3);
sum=(-4*R*U*s1/Re)+(2*s2/(3*Re*De*R));
end
dy(2)=(-1.5*U^2+Cp*((1+We)*(1/R)^(3*k)-We/R-(1+delt*sin(t))))/R+sum;
for i=1:n
epsi=abs(2*sqrt(3)*R^2*U/(R^3+yii(i)));
dy(2+i)=(1/(t+0.0001)^bta)*(-k1*Str(i)*epsi+k2*(epsi)^0.5*(1-Str(i))+k3*(1-Str(i)));
inv2sqrt=(k2*(epsi)^0.5*+k3)/(k1*epsi+k2*(epsi)^0.5+k3);
dy(n+2+i)=(k4^bta/(t+0.0001)^bta)*(MuR+inv2sqrt)*gamRR(i)*(4*R^2*U/(R^3+yii(i)));
dy(2*n+2+i)=-(k4^bta/(t+0.0001)^bta)*(MuR+inv2sqrt)*gamTT(i)*(2*R^2*U/(R^3+yii(i)));
end
end

Sign in to comment.

Categories

Find more on Programming in Help Center and File Exchange

Products

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!