How to repeat the matrix to complete the shape of Matrix

Hello everyone i hope you are doing well.

I have the following Dataset,

one has shape of 1x586 and other has shape 1x48.

I want to repeat this matrix to to complete the shape of 1x1000 and 1x10000.

How can i do this in MATLAB

[Rik]

What have you tried so far?

Also, 48 and 586 are not integer fractions of 1e3 and 1e4. How do you want to deal with that?

Answer 1

[Walter Roberson]

Your requirements are not clear.

targetsize586 = 10000;
n586 = numel(Mat_586);
nrep = targetsize586 / n586;

fullrep = floor(nrep);
leftover = targetsize - fullrep * n586;

variation1 = [repmat(Mat_586, 1, fullrep), Mat_586(1:leftover)];

variation2 = repelem(Mat_586, 1, ceil(nrep)); variation2(targersize586+1:end) = [];

variation1 makes repeated copies of the matrix, like [1 2 3, 1 2 3, 1 2 3, 1 2 3, ...] as many times as possible to fit within the target size, and then makes a partial copy as large as needed to fit.

variation2 makes repeated copies of the elements, like [1 1 1 1, 2 2 2 2, 3 3 3 3, ...] with each element repeated as many times as needed until the overall would meet or exceed the target size, and then trims off enough copies of the last element to make the overall fit. So you might, for example, get 21 copies in a row of each value except the last, followed by (say) 18 copies of the last element.

[Stephen john]

@Walter Roberson

This one Also i want to checkif there is already 10000 sample in each row

then there should no replication

targetsize586 = 10000;
n586 = numel(Mat_586);
nrep = targetsize586 / n586;
fullrep = floor(nrep);
leftover = targetsize - fullrep * n586;
variation1 = [repmat(Mat_586, 1, fullrep), Mat_586(1:leftover)];

[Walter Roberson]

Go on to the next row of what? Check if 1000 samples are present in what?

[Stephen john]

@Walter Roberson for example i have the following data shape of 1x1176

i want 1000 samples and dthe remaining 176 in the next row and apply same repeat function on second row

[Walter Roberson]

Okay, the 1176 example. When filling in the second row, should you start back from the beginning of the 1176, or should you only start from the part after 1000?

[m1, m2, ... m1000
 m1001, m1002, ... m1176, m1, m2, ... m824]

or

 [m1, m2, ... m1000
 m1001, m1002, ... m1176, m1001, m1002, ... m1176, m1001, m1002, ...]

[Stephen john]

@Walter Roberson The second row start after 1000 means the first value of second row is 1001

[Walter Roberson]

Yes, that is not the question. The question is what happens when you need to start repeating values to fill up the second row.

Notice in the first possibility, after the last of the original entries, m1176, I start repeating from the first over-all entry, m1.

Notice in the second possibility, after the last of the original entries, m1176, I start repeating from the first value that is on this same row, m1001.

It is not clear which of these two possibilities you are after?

Suppose the input data was exactly 1001 elements long. Then should the output be

[m(1:1000);
 m(1001), m(1:999)]

or should it be

[m(1:1000);
 repmat(m(1001), 1, 1000)]

[Stephen john]

@Walter Roberson let me explain it to you , let my dataset shape 1176

The first row contain 1000 samples and they repeat copies of the matrix upto 10000 to complete 1st row

the n in second row 176 samples and they should repeat copies of the matrix upto 10000 to complete second row..

the output shape is 2x10000

[Walter Roberson]

targetsize = 10000;

output = [];
temp = reshape(YourData, 1, []);   %ensure row
nt = numel(temp);
while nt >= targetsize
    output = [output; temp(1:targetsize)];
    temp = temp(targetsize+1:end);
    nt = numel(temp);
end
nrep = ceil(targetsize / nt);   %we know nt < targetsize at this point
temp = repmat(temp, 1, nrep);
output = [output; temp(1:targetsize)];