R-square and the F statistic... error

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Hi everyone, I am getting this error for the each line (Warning: R-square and the F statistic are not well-defined unless X has a column of ones.).
I have looked up other similar questions but couldn't use the solutions for my case. Help if you can please. Thanks.
for r=1:size(Sun,1)
[~,~,~,~,STATNm(r,:)]=regress(Sun(r,:)',MHL(r,:)');
[~,~,~,~,STATNc(r,:)]=regress(Sun(r,:)',LComb(r,:)');
[~,~,~,~,STATSm(r,:)]=regress(Ssun(r,:)',Sm(r,:)');
[~,~,~,~,STATSc(r,:)]=regress(Ssun(r,:)',CLS2(r,:)');
[~,~,~,~,STATSml(r,:)]=regress(Nsun(r,:)',Nml(r,:)');
[~,~,~,~,STATSlc(r,:)]=regress(Nsun(r,:)',Nlc(r,:)');
end
Rsq=[STATNm(:,1) STATNc(:,1) STATSm(:,1) STATSc(:,1) STATSml(:,1) STATSlc(:,1)]';

Accepted Answer

Walter Roberson
Walter Roberson on 3 May 2022
MHL(r, :) is a row. You transpose it to a column and pass it as the second parameter to regress(). That is a column vector, not a 2d matrix.
As it only has one column, we can be sure that there is no trailing column of 1's. But having a column of 1's is needed for regression to work properly, since it is needed to estimate the constant term.
  2 Comments
Walter Roberson
Walter Roberson on 4 May 2022
Whether you put the ones as the first column or the second column does not matter, other than it will switch the order of the results, with the intercept going into whichever column has the ones.

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More Answers (1)

Asliddin Komilov
Asliddin Komilov on 4 May 2022
Edited: Asliddin Komilov on 4 May 2022
Thanks, it seems I got rid of the warning but have another one: "Warning: X is rank deficient to within machine precision. "
Any idea what I shall do now? Thanks.
Cones1=ones(size(Sun,2),1);
Cones2=ones(size(Ssun,2),1);
for r=1:size(Sun,1)
[~,~,~,~,STATNm(r,:)]=regress(Sun(r,:)',[Cones1 MHL(r,:)']);
[~,~,~,~,STATNc(r,:)]=regress(Sun(r,:)',[Cones1 LComb(r,:)']);
[~,~,~,~,STATSm(r,:)]=regress(Ssun(r,:)',[Cones2 Sm(r,:)']);
[~,~,~,~,STATSc(r,:)]=regress(Ssun(r,:)',[Cones2 CLS2(r,:)']);
[~,~,~,~,STATSml(r,:)]=regress(Nsun(r,:)',[Cones2 Nml(r,:)']);
[~,~,~,~,STATSlc(r,:)]=regress(Nsun(r,:)',[Cones2 Nlc(r,:)']);
end
Rsq=[STATNm(:,1) STATNc(:,1) STATSm(:,1) STATSc(:,1) STATSml(:,1) STATSlc(:,1)]';
  3 Comments
Walter Roberson
Walter Roberson on 5 May 2022
I do not think 0 itself is a problem, but I think you could have a problem if you you had duplicate rows. If that can happen then I would suggest using unique() by rows, recording the second output as well, and using that second output to index the rows of the other array, using that along with the first output of unique()

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