BUG in dec2hex
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Stephen23
on 4 Sep 2023
Edited: Stephen23
on 4 Sep 2023
You do not explain what the problem is.
Note that your last example uses DOUBLE class and not UINT64, which clearly has a different bit pattern:
u = bitxor(uint64(0xFF000000),0xFFFFFFFFFFFFFFFF)
dec2hex(u)
d = double(u) % The same value you entered by hand
dec2hex(d)
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