Clear Filters
Clear Filters

i not able to find error..not getting right plot

1 view (last 30 days)
clc;
clear all;
k=1;
g=0.01:.1:6;
lambda=2;
b=2;
c=1;
l=2;
for x=0.01:.1:6
T=[];
P=(0.5*lambda)/((b^(lambda*c))*gamma(c));
Q=(k^0.5)*l^(lambda*c-0.5)/((2*pi)^(0.5*(l+k)-1));
R=evalin(symengine, sprintf('meijerG([[1],[]], [[1,0.5],[]],%f)',x^2));
T=[T P*Q*R];
end
plot(g,T)

Accepted Answer

dpb
dpb on 17 Aug 2015
for x=0.01:.1:6
T=[];
...
T=[T P*Q*R];
end
plot(g,T)
You wipe out T every pass thru the loop so the result is simply the last P*Q*R computed. Move that outside the loop altho "growing" an array like this dynamically is not good practice; use preallocation and fill instead.
T=zeros(size(0.01:0.1:6)); % preallocate
ix=0; % array index
for x=0.01:0.1:6
...
ix=ix+1;
T(ix)=P*Q*R;
end
Or, use the loop for an integer variable and compute x dynamically as x=x+dx;
  4 Comments
dpb
dpb on 18 Aug 2015
In that case, you've got to allocated a square array instead of a vector and store into it...
T(ix,:)=P*Q*R;

Sign in to comment.

More Answers (0)

Categories

Find more on Creating and Concatenating Matrices in Help Center and File Exchange

Tags

No tags entered yet.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!