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Passing the input argument to the class

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I need to know how can i pass the input argruments received from other function to the class
for example i got a function
function[a,b,c] = getdata(datalength, stringlength)
so now i need to pass the input arguments to the class created. How can i do it??

Accepted Answer

Adam
Adam on 27 Jul 2016
If your class constructor takes arguments then just
[a, b, c] = getdata( datalength, stringlength );
myObj = myClass( a, b, c );
or if you already have an object then you need some function that accepts the 3 arguments. It is hard to say if you post nothing about your class and when/how/where it is constructed.

More Answers (1)

Ahmad Azn
Ahmad Azn on 25 Oct 2019
hi guys
please help me!
how can i run this m-file?
%function [F,U,R]=ST(D)
% Analyize a Truss using the direct stiffness method
%
% Input D defines the Truss structure as follows
% D.Coord -- N x 3 array of node coordinates
% D.Con -- N x 2 array of connector or member mapping
% D.Re -- N x 3 array of node freedom 1 = fixed 0 = free
% D.Load -- N x 3 array of load force vectors
% D.A -- M x 1 array of member cross section areas
% D.E -- M x 1 array of member Elasticity ( Youngs Modulous)
%
% Ouput F -- M x 1 array of force along members
% U -- N x 3 array of Node displacement vectors
% R -- N x 3 array of Reaction force vectors
%% History
% Original code by Hossein Rahami
% 17 Mar 2007 (Updated 13 Apr 2007)
% Reformatted and comments added by
% Frank McHugh 06 Sep 2012
function [F,U,R]=ST(D)
w=size(D.Re); % 3 x number of nodes
S=zeros(3*w(2)); % stiffness matrix is 3*(number of nodes) square matrix
U=1-D.Re; % U is displacement matrix [
% column index by node
% x , y , z by rows
% initialize U to 1 for non fixed nodes 0 for fixed
f=find(U); % f index in U of free nodes
for i=1:size(D.Con,2) % Loop through Connectors (members)
H=D.Con(:,i);
C=D.Coord(:,H(2))-D.Coord(:,H(1)); % C is vector for connector i
Le=norm(C); % Le length of connector i
T=C/Le; % T is unit vector for connector i
s=T*T'; % Member Siffness matrix is of form
% k * | s -s |
% | -s s | in global truss coordinates
G=D.E(i)*D.A(i)/Le; % G aka k stiffness constant of member = E*A/L
Tj(:,i)=G*T; % Stiffness vector of this member
e=[3*H(1)-2:3*H(1),3*H(2)-2:3*H(2)];
% indexes into Global Stiffness matrix S for this member
S(e,e)=S(e,e)+G*[s -s;-s s];
% add this members stiffness to stiffness matrix
end
U(f)=S(f,f)\D.Load(f); % solve for displacements of free nodes
% ie solve F = S * U for U where S is stiffness
% matrix.
F=sum(Tj.*(U(:,D.Con(2,:))-U(:,D.Con(1,:))));
%project displacement of each node pair on to member
% between
% f = Tj dot ( U2j - U1j ). Then sum over all contributing
% node pairs.
R=reshape(S*U(:),w); % compute forces at all nodes = S*U
R(f)=0; % zero free nodes leaving only reaction.
end
  1 Comment
Steven Lord
Steven Lord on 25 Oct 2019
This isn't related to the topic of the original question except very loosely (they're both about calling functions.) Please ask this as a new question.

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