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I want to generate a fixed percent of random points on a straight line joining two points.

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SUSHMA MB
SUSHMA MB on 3 Aug 2016
Edited: SUSHMA MB on 3 Aug 2016
I want to generate 5 percent of the randomly generated numbers in a fixed straight line equation. For example, i have two points (x1, y1) and (x2, y2), and now i have drawn a straight line between the two points, with the help of straight line equation. Now i want 100 random numbers to be generated out of which 5 percent of those random numbers should fall in the straight line that is joined between the two points.

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José-Luis
José-Luis on 3 Aug 2016
What have you tried so far? Look at rand().
Outside is a very vague term. The metro station is just outside my office. Betelgeuse is outside my office. Gn-Z11 is outside my office.
SUSHMA MB
SUSHMA MB on 3 Aug 2016
Let the
XY_BOUNDARY = [0,70,0,50};
position = [XY_BOUNDARY(2) - XY_BOUNDARY(1); XY_BOUNDARY(4) - XY_BOUNDARY(3)] .* rand(2,1) ...
+ [XY_BOUNDARY(1);XY_BOUNDARY(3)];
In the above code i get a random number within the specified boundary. Now i want the random point position in a specified boundary as well as on the line connecting two points (x1,y1), and (x2,y2)...Please tell me how to do this

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Accepted Answer

Torsten
Torsten on 3 Aug 2016
Instead of generating 100 random numbers, use "rand" to generate 5 random numbers on [0:1] and set the points to
lambda=rand(5,1);
x=x1+lambda*(x2-x1);
y=y1+lambda*(y2-y1);
Best wishes
Torsten.

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SUSHMA MB
SUSHMA MB on 3 Aug 2016
But can you plz tell me that, if 100 points are their, then how can i make atleast 5 points to appear it on a line
SUSHMA MB
SUSHMA MB on 3 Aug 2016
Let the
XY_BOUNDARY = [0,70,0,50};
position = [XY_BOUNDARY(2) - XY_BOUNDARY(1); XY_BOUNDARY(4) - XY_BOUNDARY(3)] .* rand(2,1) ...
+ [XY_BOUNDARY(1);XY_BOUNDARY(3)];
In the above code i get a random number within the specified boundary. Now i want the random point position in a specified boundary as well as on the line connecting two points (x1,y1), and (x2,y2)...Please tell me how to do this

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