How and when to use sprintf disp ?....

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Luca
Luca on 15 Aug 2017
Edited: Luca on 16 Aug 2017
Hi guys, I m italian (excuse me for my english) and I have a question about sprintf (disp,..):
My code is :
for k=1:1:Matrice_Gruppi(1, end)
c1={nomi_famiglie};
c2={Matrice_Gruppi(5, k)};
sprintf('\n %s paga %s euro.',c1{1},c2{1});
end
I simply would
  1. Insert with keybord a string and to save it into nomi_famiglie then
  2. To print values of nomi_famiglie and Matrice_Gruppi on command window (inizially, then I would create a interface).
I see the error:
Undefined function or variable 'sprinf'.
Could you help me please?
Thanks and bye
  4 Comments
Stephen23
Stephen23 on 16 Aug 2017
@Luca Filippone: I think you should be using
for k = 1:numel(Matrice_Gruppi)
Luca
Luca on 16 Aug 2017
Edited: Luca on 16 Aug 2017
All works, thanks

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Accepted Answer

Image Analyst
Image Analyst on 15 Aug 2017
Edited: Image Analyst on 15 Aug 2017
There is no function sprinf(). Use sprintf(), with a "t", instead.
Or better yet, don't use cell arrays:
for k=1:1:Matrice_Gruppi(1, end)
myStrings{k} = sprintf('%s paga, %f euros.\n',...
nomi_famiglie, Matrice_Gruppi(5, k));
end
celldisp(myStrings);
assuming Matrice_Gruppi is an array of doubles, not strings like you implied by using %s.
  5 Comments
Stephen23
Stephen23 on 16 Aug 2017
@Luca Filippone: because you forgot to read the input documentation, and learn that you need to use the 's' option for strings:
txt = 'Inserisci nome famiglia: ';
str = input(txt,'s')
Image Analyst
Image Analyst on 16 Aug 2017
You showed in your comment above that Matrice_Gruppi is a 5 by 1 array. And Matrice_Gruppi(1,end) = 520.2000. So in your sprintf when you're trying to access Matrice_Gruppi(5, k) when k = 1,2,3,4,5,.....520, will fail because there is no columns beyond 1.

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