How to make it a one line code?

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matrix= [1 0 -1 0.001 4; 5.9 -1 3.15 1 1.11 ] ;
cell_conv = (num2cell(matrix));
find_one = abs( matrix ) == 1 ;
cell_conv(find_one)={'hey'}
  2 Comments
oshawcole
oshawcole on 6 Dec 2017
cell_conv = (num2cell(matrix));
find_one = abs( matrix ) == 1 ;
cell_conv(find_one)={'hey'}
Merging these three to one line. how do I put num2cell in the single line code you gave?

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Accepted Answer

Walter Roberson
Walter Roberson on 6 Dec 2017
It is possible to do in one line, but it gets so messy that it is not recommended.
Here is a way to do it with the assistance of a helper function.
IDXAT = @(M,IDX) M(IDX);
disp(IDXAT(cat(3,num2cell(matrix),repmat({'hey'},size(matrix))), reshape(1:numel(matrix), size(matrix))+numel(matrix)*(abs(matrix)==1)))
The output would look like
'hey' [ 0] 'hey' [0.001] [ 4]
[5.9] 'hey' [3.15] 'hey' [1.11]
I am not sure that is acceptable to you.
  2 Comments
Walter Roberson
Walter Roberson on 6 Dec 2017
The above is the cleaner version -- doing it with one line would have required using the internal function subsref(), which I do not recommend that anyone deliberately use unless they are implementing object classes.

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More Answers (1)

Jos (10584)
Jos (10584) on 6 Dec 2017
Here is another but shorter two-liner using a functional programming approach for anonymous function:
matrix= [1 0 -1 0.001 4; 5.9 -1 3.15 1 1.11 ]
iif = @(varargin) varargin{2 * find([varargin{1:2:end}], 1, 'first')}() ;
% functional programming of a "if ... elseif ... else" construction
out = arrayfun(@(X) iif(isequal(abs(X),1), @() 'hey', true, @() X), matrix, 'un', 0)
  3 Comments
Walter Roberson
Walter Roberson on 8 Dec 2017
Ah, I remember now why I had forgotten Loren's solution: it was because I cannot think of any way of tricking MATLAB to return something for commands that return no output. For example if one of the branches was
@(x) set(handles.push7, 'Value', x)
and the other branch was
@(x) fprintf('hey')
then the fprintf() officially returns the number of bytes emitted so it can be used in arrayfun, but the set() has no output and cannot be used, not even when 'uniform', 0 is used.
I suppose I could write a real function
function yelm = empty(function_handle);
function_handle();
yelm = [];
end
and then code with
@(x) empty( @() set(handles.push7, 'Value', x) )
But I dislike having to write true functions to implement functional programming.
I know in HG2 that I could write
handles.push7.Value = x
and that returns handles.push7, but assignment in functional programming is ugly in MATLAB... though you can get this particular one to work:
newval = arrayfun(@(x) subsasgn(handles.push7, struct('type','.','subs','Value'), x),randi(7,1,5))
The output variable is mandatory in this situation.

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