Subscripted assignment dimension mismatch when cal back the function
1 view (last 30 days)
Show older comments
shahin hashemi
on 24 Dec 2017
Answered: Image Analyst
on 24 Dec 2017
dear all this is my cod
function [Rl] = basisfunction1(j,N)
L=1;
x = sym('x', [1 3], 'real');
for i=j-1
Rl(:,:,j)=[cos(x(3*i-2))*cos(x(3*i-1))*cos(x(3*i))-sin(x(3*i-2))*sin(x(3*i)) -cos(x(3*i-2))*cos(x(3*i-1))*sin(x(3*i))-sin(x(3*i-2))*cos(x(3*i)) cos(x(3*i-2))*sin(x(3*i-1));sin(x(3*i-2))*cos(x(3*i-1))*cos(x(3*i))+cos(x(3*i-2))*sin(x(3*i)) -sin(x(3*i-2))*cos(x(3*i-1))*sin(x(3*i))+cos(x(3*i-2))*cos(x(3*i)) sin(x(3*i-2))*sin(x(3*i-1));-sin(x(3*i-1))*cos(x(3*i)) sin(x(3*i-1))*sin(x(3*i)) cos(x(3*i-1))];
end
end
and i save it in basisfunction1.m and i run my main cod in other m file that is like :
N=1;
for j=2:N+1
Rl(:,:,j) = basisfunction1(j,N);
end
but i get this error : Subscripted assignment dimension mismatch
i realy apreciated if some one can help
0 Comments
Accepted Answer
Image Analyst
on 24 Dec 2017
basisfunction1 returns a 3-D array R1. Now in
Rl(:,:,j) = basisfunction1(j,N);
you're trying to stick a 3-D array into one plane of the R1 array. You can only put a 2-D image into the j'th plane, not a 3-D image.
0 Comments
More Answers (0)
See Also
Categories
Find more on Creating and Concatenating Matrices in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!