Help with conidtional loops?
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Everything in the code works like I want it to except I need the code to end if a guess is higher than 10. it will display 'dumb' but also needs to end the program. I can't get it to break the code.
%%Guess Number Game
R=floor ( rand()*10 );
count=0;
for i=0:5
while(i~=5)
guess=input('Guess a number between 0 and 10')
if (R>guess)
disp('Your Guess Is Too Small')
elseif (R<guess)
disp('Your Guess Is Too Large')
elseif (R==guess)
disp('You are Correct! It is')
end
if (guess>10)
disp('DUMB')
break;
end
count=count+1
if count==3;
disp ('You Failed The Game, Try Again')
count=0;
break;
end
end
end
2 Comments
Walter Roberson
on 19 Jul 2018
Why are you using while inside of for? The body of your while never modifies i, so the while loop is not going to end until it hits one of the two "break" statements.
Your current code would play the game 5 times, once for i = 0, once for i = 1, 2, 3, 4. Then your "for" loop extends to i = 5, but your while excludes that case so nothing would be done for that case, so why bother to have the while, why not just end i at 4 ?
Accepted Answer
More Answers (1)
OCDER
on 19 Jul 2018
Edited: OCDER
on 19 Jul 2018
Keep track of how many games and how many trials were done, and the status of the game as WonGame = 0 or WonGame = 1.
%%Guess Number Game
WonGame = 0;
GameCount = 0;
while ~WonGame
if GameCount >= 5
disp('You Failed The Game 5 Times! No more!')
break
end
R = randi(9); %floor( rand()*10 );
Guess = Inf;
count = 0;
while 1
%guess = round(input('Guess a number between 0 and 10: ')); %DID YOU WANT IT 0,..., 10? or 1,...,9???
guess = round(input('Guess an integer between 0 and 10: '));
if guess>=10 || guess <= 0
disp('DUMB. Integer must be > 0 and < 10.')
elseif (R>guess)
disp('Your Guess Is Too Small')
elseif (R<guess)
disp('Your Guess Is Too Large')
elseif (R==guess)
disp('You are Correct! It is')
WonGame = 1;
break
end
count = count + 1;
if count == 3
disp('You Failed The Guess in 3 Tries')
disp(['Answer was: ' num2str(R)]);
break
end
end
GameCount = GameCount + 1;
end
2 Comments
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