Gauss forward interpolation formula
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n = length(x)
I created the difference table (tbl) using the following code. difference table is in attached file
tbl=y';
for j=2:n
for i=1:n-j+1
tbl(i,j)=tbl(i+1,j-1)-tbl(i,j-1);
end
end
p = (xp – x0) / h
yp = y0 + p.dy0 + p(p-1) (d2 y-1 + d3 y-1 ) / 2! + p(p-1) (p-2) (d3 y-1 + d4 y-1 ) / 3! +
p(p-1) (p-2)(p-3) (d4 y-1 + d5 y-1 ) / 4! + p(p-1) (p-2)(p-3)(p-4) (d5 y-1 + d6 y-1 ) / 5!
I created a vector with the terms 1, p, p(p-1), p(p-1)(p-2)…p(p-1)(p-2)..(p-(n-2)) as t=cumprod([1,p-(0:n-2)]);
Now, suggest me the code to create a vector with the following terms
y0 , dy0 , (d2 y-1 + d3 y-1 ) / 2! , (d3 y-1 + d4 y-1 ) / 3! , (d4 y-1 + d5 y-1 ) / 4! ,
(d5 y-1 + d6 y-1 ) / 5! , …….
4 Comments
Anton Gluchshenko
on 18 Nov 2020
Edited: Anton Gluchshenko
on 18 Nov 2020
Sorry. But It is not your code... or?
Ismail Khan Totakhil
on 18 Mar 2021
Good one sir, can u show me the code of Newton backwards interpolation... Thank u sir..
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