How to cell array of string to 3D matrix?
2 views (last 30 days)
Show older comments
Danupon Subanapong
on 15 Nov 2018
Commented: Danupon Subanapong
on 15 Nov 2018
I have a cell array with size 200x1 with each cell having a string array 12000x1 cell. Example of string array with size 12000x1 will be in the attached file. How can i convert this cell into a 3d numeric matrix array of size 12000x5x200 ?? Thank you in advance.
2 Comments
Stephen23
on 15 Nov 2018
Edited: Stephen23
on 15 Nov 2018
"I have a cell array with size 200x1 with each cell having a string array 12000x1 cell"
But what you uploaded is a 12000x1 cell array, where each cell contains a character vector.:
>> size(AB)
ans = 12000 1
>> all(cellfun('isclass',AB,'char'))
ans = 1
Your question and your supplied data do not match.
Accepted Answer
Stephen23
on 15 Nov 2018
Edited: Stephen23
on 15 Nov 2018
This converts your supplied cell array (attached) into a numeric array:
>> C = cellfun(@(s)sscanf(s,'%f'),AB,'uni',0);
>> A = cat(3,C{:});
>> size(A)
ans =
5 1 12000
Note that your data description does not match the data in your .mat file.
2 Comments
Stephen23
on 15 Nov 2018
Edited: Stephen23
on 15 Nov 2018
Two methods that work with the data in your second example file.
Method one: cellfun and cellmat:
>> load Example_of_cell2.mat
>> F = @(s) sscanf(s,'%f',[1,Inf]);
>> A = cell2mat(cellfun(F,cat(3,BB{:}),'uni',0));
>> size(A)
ans =
12000 5 200
Method two: sprintf, reshape and permute:
>> C = [BB{:}];
>> B = sscanf(sprintf('%s\v',C{:}),'%f');
>> B = permute(reshape(B,[5,12000,200]),[2,1,3]);
>> size(B)
ans =
12000 5 200
Method two is quite possibly faster. Comparing the outputs:
>> isequal(A,B)
ans = 1
More Answers (0)
See Also
Categories
Find more on Data Type Conversion in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!