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How to output a variable from a loop as a large array

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I'm hoping to output the variable 'fluxset' from a loop into an array which would store all the outputs into one large array.
I have tried a fluxset(month)=... array storage method to no luck, I also tried outputting the variable as a series of .mat files using the sprintf function to name the files however the variable names were all the same and I could not fix this issue due to a supposed 'dynamic variable naming' issue.
My code is approx. in the form:
for year=[1993:2007]
for month=[1:12]
...
fluxset=[fluxa;fluxb;fluxc]
end
end
I hope to either store an all loop outputs array or alternatively a year by year output array.
If anyone could help, I would be greatly appreciative.
  5 Comments
Josh
Josh on 12 Jul 2012
fluxa... are all 1x1, so subsequently fluxset is 3x1
Conrad
Conrad on 12 Jul 2012
Could try:
years = 1993:2007;
months = 1:12;
fluxset = zeros(numel(years),numel(months),3);
for year = years
for month = months
fluxset(year-years(1)+1,month-months(1)+1,:) = [1 1 1]';
end
end
Note that I used dummy values [1 1 1]' in place of [fluxa;fluxb;fluxc].
Conrad

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Accepted Answer

Michelle
Michelle on 12 Jul 2012
If I understand you right - I THINK you want the information from each loop to be added on to the array right? If so, this could work but creating a different variable - one that gets recomputed with each loop, adn then the "master" variable that gets the recomputed varible added on to it with each loop:
fluxset = [];
for year=[1993:2007]
for month=[1:12]
fluxset0=...%Computations here;
fluxset = [fluxset; fluxset0];
end
  1 Comment
Josh
Josh on 13 Jul 2012
Thank you Michelle and all who have assisted, you've saved me hours of mind-numbing file editing.

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More Answers (1)

Jan
Jan on 12 Jul 2012
And with the important pre-allocation:
n = (2007 - 1993 + 1) * 12;
fluxset = zeros(n, 3); % Pre-allocate!
index = 0;
for year = 1993:2007
for month=[1:12]
...
index = index + 1;
fluxset(index, :) = [fluxa, fluxb, fluxc];
end
end

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