Missing factor using rule of three?
2 views (last 30 days)
Show older comments
Hello,
I try to calculate a distance in meter, given the rad values. I use the follwing formula, which is really easy.
0.004 x (m)
--------- = ----------
2*pi y (rad)
If I want to know which x(m) corresponds to 4*pi the formula becomes
(0.004*4*pi)/(2*pi)=2*0.004=0.008
This is a result I would expect, but putting the same formula into matlab or any calculator results in
(0.004*4*pi)/2*pi
ans=
0.078956
Next to a missing magnitude it is not 100% correct as well. I think one reason is limited digits of pi, but why is a magnitude missing?
I am sorry for such a trivia question, but maybe someone could give me a hint. I propably think in a wrong direction.
0 Comments
Accepted Answer
the cyclist
on 13 Mar 2019
Edited: the cyclist
on 13 Mar 2019
Try
(0.004*4*pi)/(2*pi)
The reason your syntax does not work is that it will divide by 2, and then multiply by pi.
More Answers (0)
See Also
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!