# How to fix following error?

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Yasir Ali on 27 Mar 2019
Commented: Walter Roberson on 29 Mar 2019
Hello Seniors, How to Solve following error I tried but failed to solve it.
t=0:0.300:0.050:0500; x=chirp (t,0,1,150); F=0:0.1:100; [y,f,t,p]=spectrogram(x,256,250,F,1E3,'yaxis');
Error using welchparse>segment_info (line 88)The length of the segment cannot be greater than the length of the input signal.
I will provide full code if anyone need actually my problem is to get voice frequency in miliseconds.
Adam Danz on 27 Mar 2019
There is no picture. A screen shot isn't really useful (if that's what you were going to share). People can't copy/paste a screen shot into their matlab workspace.
Yasir Ali on 27 Mar 2019
Edited: Stephen23 on 27 Mar 2019
here is complete error and also see full code below ,in which I can get good result but when I do some variation in code it shows error.
>> t=0.400:0.050:0.500;
>> x=chirp(t,0,1,150);
>> F = 0:.1:100;
>> [y,f,t,p] = spectrogram(x,256,250,F,1E3,'yaxis');
Error using welchparse>segment_info (line 188)
The length of the segments cannot be greater than the length of the input signal.
Error in welchparse (line 32)
[L,noverlap,win] = segment_info(M,win,noverlap);
Error in spectrogram (line 172)
[x,nx,~,~,~,win,~,~,noverlap,~,~,options] = welchparse(x,esttype,varargin{:});
full code which works for frequeency spectrum in miliseconds.
t=0:0.001:2; % 2 secs @ 1kHz sample rate
x=chirp(t,0,1,150); % Start @ DC, cross 150Hz at t=1sec
F = 0:.1:100;
[y,f,t,p] = spectrogram(x,256,250,F,1E3,'yaxis');
% NOTE: This is the same as calling SPECTROGRAM with no outputs.
surf(t,f,10*log10(abs(p)),'EdgeColor','none');
axis xy; axis tight; colormap(jet); view(0,90);
xlabel('Time');
ylabel('Frequency (Hz)');
NW = round(fs*0.025);
[S,F,T,P] = spectrogram(y(:,1),NW,[],[],fs);
% Then to plot:
subplot(2,1,1),pcolor(T,F,log10(P)),
caxis([-6 0]+max(caxis))
colorbar
subplot(2,1,2)
semilogy(F,P(:,23))
title(sprintf('PSD at time: %f',T(23)))
xlabel('Frequency (Hz)')

Walter Roberson on 28 Mar 2019
You assign a vector to t before the code, but you name t as an output parameter in the spectrogram() call. If you then try to use t after that, it is now only 3 x 1 and you have a problem.
The problem is not the first run: the problem is overwriting t but still expecting t to have the same meaning.
Walter Roberson on 29 Mar 2019
2 kHz is increment 1/2000 which is 0.0005
Walter Roberson on 29 Mar 2019
The general formula is:
time = (0:number_of_samples-1) / sampling_frequency

Adam Danz on 27 Mar 2019
"Error: The length of the segments cannot be greater than the length of the input signal."
When you're using miliseconds, your x input contains 2001 samples and your window value of 256 breaks up the 2001 values into 256 segments. That works fine. The reason your code is breaking with the other set of parameters is that your x input only contains 3 samples but your window value is still 256. As the error message indicates, the number of segments can't be greater than the number of samples in x.
Adam Danz on 28 Mar 2019
Walter is a senior in this forum. I'm a novice compared to him :D
INow I understand that your data have a duration of 5 seconds and that you want the time variable to be at ms resolution. One more bit of information is missing: the interval of your data or the number of samples.
For example
t = 0:0.001:5;
length(t) % = 5001
gives you 5 seconds at 1ms intervals while
t = 0:0.005:5;
length(t) % = 1001
gives you 5 seconds at 5 ms intervals.
Or maybe you want 501 samples between 0 and 5 sec. That would be
linspace(0,5,501)
For now don't worry about being new at Matlab. I think the more important step is to be able to explain what you're trying to do (without worrying how to do it, for now).
Yasir Ali on 29 Mar 2019
Dear@Adam thank u for your comment, My main object is to compare frequencies of male and female voices I want to find out difference between male and female voices through frequencies after than I will recognise particular male voice by assigning frequency.