# how to change axis of a matix?

16 views (last 30 days)
Asliddin Komilov on 13 Sep 2019
Edited: Bruno Luong on 15 Sep 2019
my matrix is M(x,y,z) where:
x=1:90
y=1:3:120
z=1:40
and
c=y./z
and I need to convert M into N(x,c).
Any ideas?
Walter Roberson on 14 Sep 2019
No, length of y and z are the same and y./z would have the same length.
Some of what you wrote does not seem to make sense until you start talking about grids of data, but then you have to ask about the sizes of the grids.

Bruno Luong on 15 Sep 2019
Edited: Bruno Luong on 15 Sep 2019
Ufun = @(X,Y,Z) X;
Vfun = @(X,Y,Z) Y./(Z+200);
[X,Y,Z] = ndgrid(x,y,z);
U = Ufun(X,Y,Z);
V = Vfun(X,Y,Z);
U = U(:);
V = V(:);
[umin,umax] = bounds(U);
nu = 21;
u = linspace(umin,umax,nu);
[vmin,vmax] = bounds(V);
nv = 21;
v = linspace(vmin,vmax,nv);
[~,~,I] = histcounts(U,u);
[~,~,J] = histcounts(V,v);
N = accumarray([J I], M(:), [nu nv]-1, @mean, NaN);
midfun = @(x) 0.5*(x(1:end-1)+x(2:end));
u = midfun(u);
v = midfun(v);
surf(u,v,N);
xlabel('u (=x)');
ylabel('v (=y/(200+z)');

### More Answers (1)

Walter Roberson on 14 Sep 2019
[X, Y, Z]=ndgrid(1:90,1:3:120,1:40);
C = round(ceil(Y./Z));
N = accumarray([X(:), C(:)], M(:), [], @mean, nan);
surf(N, 'edgecolor', 'none')
xlabel('x')
ylabel('c')
Or possibly N.' instead of N
Walter Roberson on 15 Sep 2019
(y-z)/y is 1-z/y and since z and y both include 0, you still have nan and infinities.

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