Reading a vector in intervals of 40.

Hi. Good day.

I would like to help me in the following:

I have a vector A

A = [14 8 12 18 8 34 24 14 12 22 2 20 2 10 16 8 10 18];

I want to add 0 to the first vector element A; 0 + 14 = 14

__ to the second element add 40; 40 + 8 = 48

__ to the third element add 80; 80 + 12 = 92

__ to the fourth element add 120; 120 + 18 = 138

__ to the fifth element add 160; 160 + 8 = 168

and so on (40 by 40).

I have tried with " for " cycles and I have not been able to do it.

In the end the searched vector would be:

[14 48 92 138 168 234 264 294 332 422 442 500 522 570 616 648 690]

Thank you

Answer 1

[Walter Roberson]

A = [14  8  12  18  8  34  24  14  12  22  2  20  2  10  16  8  10  18];

A + (0:length(A)-1) * 40

A + (0:40:40*(length(A)-1))

[Ricardo Gutierrez]

Excellent !!!!

It worked

Thank you so much.