# Fill NaN matrix with vector of unequal sizes

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Inti Vanmechelen on 18 Oct 2019
Commented: Inti Vanmechelen on 18 Oct 2019
Hi all,
I have the following code:
temp = {'AccNorm','GyrNorm'};
NSensors = 5;
for a = 1:length(temp)
for k = 1:NSensors
CMC_RT(k).RF.(temp{a}) = nan(10,2);
end
end
In which I just preallocate CMC_T with NaN values, because the 2 vectors I want to put in the matrix have different lengths.
However when I try to fill them up:
for a = 1:length(temp)
for k = 1:NSensors
CMC_RT(k).RF.GyrNorm = CMC_RTT.RF.(temp{a})(k,1:10)';
CMC_RT(k).RF.GyrNorm(:,2) = CMC_RTT.RF.(temp{a})(k,11:19)';
end
end
Matlab gives me the error: Unable to perform assignment because the size of the left side is 10-by-1 and the size of the right side is 9-by-1.
Which obviously makes sense, but I would think matlab would just fill the NaN matrix with the numbers and leave the NaN values for the ones where there is no substitute value. But this was apparently whishful thinking...
Any help on a idea for a solution would be much appreciated.
Thank you!

Stephen Cobeldick on 18 Oct 2019
CMC_RT(k).RF.GyrNorm(1:10,1) = CMC_RTT.RF.(temp{a})(k,1:10);
CMC_RT(k).RF.GyrNorm(1:9,2) = CMC_RTT.RF.(temp{a})(k,11:19);
The complex conjugates are not required.

#### 1 Comment

Inti Vanmechelen on 18 Oct 2019
Very very very stupid of me to not think of doing that myself.
Thank you.