Why d(i) is getting stored in a row vector? Shouldn't it be a single value rather than a vector!?

'x' and 'y' are column input vectors (Something like 20x1 double sorta thing).

k = input('Number of elements = ')
if k < 4
    disp Invalid
elseif k >= 4 && k <= length(x)
    for i = 1:1:k
%         z = x(i);
%         q = y(i);
        d(i) = ((x(i+1) - x(i))^2 + (y(i+1) - y(i))^2)^0.5
%        disp (d(i))
%          for i = k
%              a = sum(d(1:i))/i
%          end
    end  
    for i = 1:i
        msd = (sum(d(1:i)))/i
     %   disp (msd)
    end
elseif k > length(x)
    disp Invalid
end

Answer 1

[Sai Sri Pathuri]

Hi,

In the code, you have defined the variable d to be a vector d(i) which increases its size in each iteration of loop from 1 to k. So, it is a row vector with index j containing the value of expression at i = j.

If you expect the variable d to be a scalar which contains the value of expression

((x(i+1) - x(i))^2 + (y(i+1) - y(i))^2)^0.5 

at i = k, there is no need of loop. You can just use

d = ((x(k+1) - x(k))^2 + (y(k+1) - y(k))^2)^0.5