Does matlab have any function that can compare multiple numbers and return logical value zero or one?
41 views (last 30 days)
Show older comments
I need to find a matlab function that does this:
F(2,3,4)=0
F(2,2,2)=1
F(5,6,7,8,9,2)=0
F(6,6,6,6,6,6,6,6)=1
if all inputs that are numeric are equal, the function returns 1 and if all are not equal, function returns 0. In the first exaple, 2 and 3 and 4 are not equal so the function returned 0. In the second example all inputs are 2 so the function returned 1. Does matlab have such function?
2 Comments
David Hill
on 31 Jan 2020
You need to explain more. I cannot determine what you want. F cannot be 3,6, and 8 dimensional at the same time.
Accepted Answer
Stephen23
on 1 Feb 2020
>> F = @(varargin)isequal(varargin{:});
>> F(2,3,4)
ans = 0
>> F(2,2,2)
ans = 1
>> F(5,6,7,8,9,2)
ans = 0
>> F(6,6,6,6,6,6,6,6)
ans = 1
0 Comments
More Answers (3)
Guillaume
on 31 Jan 2020
Assuming your input is a vector:
all(diff(yourvector) == 0)
is what you want:
>> all(diff([2, 3, 4]) == 0)
ans =
logical
0
>> all(diff([2, 2, 2]) == 0)
ans =
logical
1
>> all(diff([5, 6, 7, 8, 9, 2]) == 0)
ans =
logical
0
>> all(diff([6, 6, 6, 6, 6, 6, 6, 6]) == 0)
ans =
logical
1
0 Comments
Rik
on 1 Feb 2020
Another of the many strategies: count the number of elements a unique() call gives you. (when I'm back at a computer I'll test the performance of the answers so far)
F=@(varargin) 1==numel(unique([varargin{:}]));
0 Comments
GeeTwo
on 27 Dec 2022
Edited: GeeTwo
on 27 Dec 2022
With a vector of singles or doubles, you could use ~std([a b c d]). If all the values are the same, the standard deviation will be zero, so the negation will be true.
Similar to star strider's function:
F=@(v)~std(v);
If you really want all of the inputs as separate arguments (again, singles or doubles),
function ans = allEqual(varargin)
~std(cell2mat(varargin));
end
0 Comments
See Also
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!