# making a non linear graf

3 views (last 30 days)
slowlearner on 2 May 2020
Commented: slowlearner on 2 May 2020
hey I have no idea on how to make a graf of a diminishing value for an equation i made.
It's just to represent the degradation of a battery that has a loss of 2.3% per year like this:
100(1-0.023) I've tried the for funktion but Don't think i enter correct values
would appriciate the help

darova on 2 May 2020
Do oyu have something to show? Can you attach the code? Picture
Ameer Hamza on 2 May 2020
What is the equation? '100(1-0.023)' is just a constant value.
slowlearner on 2 May 2020
Hmm.. maby f(x)=n(1-×) P(×)=f(×)(1-×) and so on x has a known value now tho

Image Analyst on 2 May 2020
Try this:
initialAmount = 100;
amountLeft = initialAmount;
maxNumberOfYears = 50;
for k = 2 : maxNumberOfYears
amountLeft(k) = amountLeft(k - 1) * (1-0.023);
fprintf('After %d years, the amount left = %.2f\n', amountLeft(k));
end
plot(amountLeft, 'b.-', 'LineWidth', 2, 'MarkerSize', 20);
grid on;
xlabel('Time (Beginning of Year)', 'FontSize', 20);
ylabel('Amount Left', 'FontSize', 20);
g = gcf;
g.WindowState = 'maximized';

#### 1 Comment

slowlearner on 2 May 2020
Nice thanks! I really need to work on my loop functions.

R2019b

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