How to make a NaN vector if there is a single NaN in a column?

Say you have a vector

A= [ 2 4 6 8 NaN 10 12 14]

How do you make a NaN vector if and only if there is a NaN in one of the columnns:

A = [NaN NaN NaN NaN NaN... ]

Answer 1

[madhan ravi]

 [m, n] = size(A);
 A = nan(m, any(isnan(A(:))) * n)

[Cnell]

Vector A would be changing for each iteration in my for loop. So, Vector A does not always have a NaN. Would that still work?

[madhan ravi]

Did you even try my code before commenting?? And indeed it’s your homework , ain’t it?

[Cnell]

I did try. It did't work for what I needed it to. Perhaps it may be another issue. Also, no it is not for homework but thank you anyway.

[madhan ravi]

It creates a NaN vector only if there’s NaN in A if not it gives an empty vector. Which is exactly what you asked in your original question. And I don’t see where it fails?

[Cnell]

It certainly does that. However, if there are no NaN in vector A, I would like for A to not be changed.

[madhan ravi]

Did you mention that in your question??

[Cnell]

I thought the "if and only if" gave that away. Perhaps I should have been more clear, my apologies.

[madhan ravi]

Sorry I’m not a mind reader:(

 ix = nan(m, any(isnan(A(:)))* n);
 if isempty(ix)
     A = A
 else
     A = ix
 end