Plotting a graph for a function with x <- seq(from=-2, to=2, len=10000) on the y axis and x on the x-axis

2 views (last 30 days)
Hi there,
I'm trying to convert code in R
f<- function(x) {(sin(sin(x^2)) + cos(x/(1+x+2*x^2)) -11/10)}
x <- seq(from=-2, to=2, len=10000)
plot(x,f(x), type='l')
abline(h=0)
to code in Matlab. I've tried a few options like fplot() but it doesn't work for a sequence.
How do I achieve this?
BTW, I'm new to both R & to Matlab
  1 Comment
Deepti Duvvuri
Deepti Duvvuri on 23 Sep 2020
Thanks so much!! Is yline the same as abline? and how do I plot a vertical abline in Matlab? Is there any documentation that I could refer to? Thank you once again!!!

Sign in to comment.

Accepted Answer

Ameer Hamza
Ameer Hamza on 23 Sep 2020
Something like this
f = @(x) (sin(sin(x.^2))+cos(x/(1+x+2*x.^2))-11/10);
x = linspace(-2, 2, 10000);
plot(x, f(x))
yline(0);
  2 Comments
Steven Lord
Steven Lord on 23 Sep 2020
Instead of creating your own yline to simulate the X axis, you could change where the X axis is drawn. I don't know if this is more to the original poster's liking.
ax = gca; % or call plot with an output and use ancestor
ax.XAxisLocation = 'origin';

Sign in to comment.

More Answers (0)

Categories

Find more on Labels and Annotations in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!