find the minimum value of x that corresponds to maximum value of theta

Hello , I have :

x=30:0.5:300;
h=180;

hypot=sqrt(x.^2+h.^2);

phi=asind(h./hypot);
theta=90-phi;

Now , I want to find the minimum value of x that corresponds to maximum value of theta. How can I do this?

Thanks!

[Sean de Wolski]

FYI, hypot() is a builtin function that does what you have above. So be careful not to overwrite it (and I recommend using it!)

x  = 1:10;
y  = 3
myHypot = hypot(x,y)

[George]

Ok, thank you!

Answer 1

[Azzi Abdelmalek]

[~,idx]=max(theta)
out=x(idx)

[George]

Can you explain me how this works?Also, if i try to change phi=asin(..) and not 'asind' according to your solution i still take the same results.Shouldn't be different?Thank you.

[Azzi Abdelmalek]

How it works: Example

x=[1 2 3 4 5 6]
y=[10 20 1 21 15 2]

The maximum value of y is 21, it corresponds to index 4, which correspond in x to x(4)

[max_value,idx]=max(y)
out=x(idx)

[George]

Ok, thanks!