Loop an if with different parameters
1 view (last 30 days)
Show older comments
Brilliant Purnawan
on 15 Nov 2020
Answered: Setsuna Yuuki.
on 15 Nov 2020
Hi, doing some practice codings and ran into a snag. So, i'm trying to plot(t,y) with different matrix 'e' values? Let's say my first 'e' would be [-1; -2; -3; -4], and second [-2; -3; -4; -5] and keeps increasing with increments of 1 until a maximum value of [-7; -8; -9; -10], and plot everything in the same graph? How would I go about this? Code is below
e = [-1; -2; -3; -4]
K = place(A,B,e);
tspan = 0:0.01:200;
if(c==-1)
y0=[0; 0; 0; 0];
[t,y] = ode45(@(t,y)Equation(y,m,M,l,g,b,-K*(y-[4; 0; 0; 0])),tspan,y0);
elseif(c==1)
y0=[-3; 0; pi+.1; 0];
[t,y] = ode45(@(t,y)Equation(y,m,M,l,g,b,-K*(y-[1; 0; pi; 0])),tspan,y0);
else
end
plot(t,y);
0 Comments
Accepted Answer
Setsuna Yuuki.
on 15 Nov 2020
You can use for to graph more than once.
for n=1:7
e = -n:-1:-n-3 % e values [-1 -2 -3 -4]
e = e'; %[-1;-2;-3;-4]
%Your code....
if(c==-1)
y0=[0; 0; 0; 0];
[t,y] = ode45(@(t,y)Equation(y,m,M,l,g,b,-K*(y-[4; 0; 0; 0])),tspan,y0);
elseif(c==1)
y0=[-3; 0; pi+.1; 0];
[t,y] = ode45(@(t,y)Equation(y,m,M,l,g,b,-K*(y-[1; 0; pi; 0])),tspan,y0);
else
end
% Your code end
plot(t,y); hold on;
end
0 Comments
More Answers (0)
See Also
Categories
Find more on Graphics Performance in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!