Find in a cell array?
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Hello all,
Suppose a cell array 10x1 consisted of random numbers from 1 to 5. How can I find the locations for number 5?
All the best,
MhD
3 Comments
Elias Berra
on 17 Nov 2015
X = my_array_data [row,col] = find(X==21) %In this example, it retrieves the cell location which contains the value 21.
Marwan Malaeb
on 20 May 2022
call this array for example X
type k=find(X==5)
it will return for you the number of the cell that has the value of 5.
Accepted Answer
Jan
on 7 Aug 2013
Edited: Jan
on 7 Aug 2013
C = {1,5,3,4,2,3,4,5,2,1};
index = find([C{:}] == 5);
Here [C{:}] is a faster inlined version of cell2mat.
Alternative:
index = cellfun(@(x) x==5, C, 'UniformOutput', 1);
Or the long and most likely faster form:
index = false(1, numel(C))
for k = 1:numel(C)
index(k) = (C{k} == 5);
end
[EDITED] If you are talking of a cell string, this is much faster:
D = {'1' '5' '3' '4' '2' '3' '4' '5' '2' '1'};
index = find(strcmp(D, '5'));
5 Comments
Jan
on 8 Aug 2013
This looks strange. When eheader is numerical, converting it elementwise inside a cellfun call to a string and afterwards by char to a char matrix is cruel. Then assuming a certain number of spaces around the value is fragile, because the width depends on the values. What about this (I cannot open the posted MAT file, better post code in the forum which creates the example data):
x = find([eheader{:}] == -88)
STRCMP works much faster with cell strings, so at least do not let CHAR() create a CHAR-matrix.
Kylie Hansen
on 16 Aug 2017
Just a casual MATLAB coder dropping by this older thread on a hunt for answers. Your response for the cell string method worked easily for me. Thank you so much for including it!
More Answers (2)
Bill Tubbs
on 15 Feb 2022
Just in case someone comes here looking to do this with a cell array of chars as I was, it's quite easy this way:
my_cell_array = {'a', 'b', 'c'};
i = find(strcmp(my_cell_array, 'b'));
assert(i == 2)
1 Comment
Caroline
on 7 Aug 2013
Edited: Azzi Abdelmalek
on 7 Aug 2013
cellarray_new = zeros; %initializing the array
ind = 1; %indices for new array
for j = 1:10
if (cellarray(j) == 5)
cellarray_new(ind) = j;
ind = ind + 1;
end
end
the array cellarray_new will contain all the indices of the original cell array that contain the number 5
3 Comments
Filza Ashraf
on 22 May 2014
how can i find a pixel intensity if cell contains an image or image is stored in cell???
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