How to get the coefficients of a fractional polynomial from syms?

I have a application which produces fractional polynomial as output as shown below,

syms x,
F=29.0*x*(5.7e-4*x + (5.58e-4*(0.0549*x - 0.0124*x*(0.00449*x - 1.0))*(4.92e-4*x - 1.0))/(0.00101*x - 1.0) - 1.0) - 0.141*x - (1.0*(0.0549*x - 0.0124*x*(0.00449*x - 1.0))*(4.92e-4*x - 1.0))/(0.00101*x - 1.0)

I need to know the co-efficients of the polynomial (F).

[Paul]

F is a rational function, i.e., the numerator and denominator are polynomials. How do you define the coefficients such a function?

[Vinothkumar Sethurasu]

If we are going for simplification as kept, F=0

The result will be a polynomila of 'x' with order 6.

I need to find the co-efficients of that polynomial.

Answer 1

[Paul]

If I correctly understand this comment (and I'm not sure I do), it sounds like you just want the coefficients of the numerator of F:

syms x
F=29.0*x*(5.7e-4*x + (5.58e-4*(0.0549*x - 0.0124*x*(0.00449*x - 1.0))*(4.92e-4*x - 1.0))/(0.00101*x - 1.0) - 1.0) - 0.141*x - (1.0*(0.0549*x - 0.0124*x*(0.00449*x - 1.0))*(4.92e-4*x - 1.0))/(0.00101*x - 1.0);
[num,den] = numden(F);
num,den

num = 

den = 

[coefficients,terms] = coeffs(num,'all')

coefficients = 

terms = 

But maybe that's still not the result you're looking for because the coeffiecients are those of a fourth order polynomial, not sixth order.