Problem 1253. Infinite precision division

Solution 3835128

Submitted on 25 Nov 2020 by Jan Olsen
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Test Suite

Test Status Code Input and Output
1   Pass
dividend = '122333444455555666666777777788888888999999999'; divisor = 42; quotient_correct = '2912701058465611111113756614021164023809523'; remainder_correct = 33; [quotient,remainder]=strdiv(dividend,divisor); while and(numel(quotient)>0,quotient(1)=='0') quotient=quotient(2:end); end assert(isequal([quotient_correct ' ' num2str(remainder_correct)],[quotient ' ' num2str(remainder)]))

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