Cody

# Problem 365. Numbers with prime factors 2, 3 and 5.

Solution 2190747

Submitted on 3 Apr 2020 by Benjamin Richards
This solution is locked. To view this solution, you need to provide a solution of the same size or smaller.

### Test Suite

Test Status Code Input and Output
1   Pass
n = 2; A_correct = 2; assert(isequal(your_fcn_name(n),A_correct))

r = 2

2   Pass
n = 3; A_correct = [2 3]; assert(isequal(your_fcn_name(n),A_correct))

r = 2 3

3   Pass
n = 4; A_correct = [2 3 4]; assert(isequal(your_fcn_name(n),A_correct))

r = 2 3 4

4   Pass
n = 5; A_correct = [2 3 4 5]; assert(isequal(your_fcn_name(n),A_correct))

r = 2 3 4 5

5   Pass
n = 10; A_correct = [2 3 4 5 6 8 9 10]; assert(isequal(your_fcn_name(n),A_correct))

q = 7 r = 2 3 4 5 6 8 9 10

6   Pass
n = 17; A_correct = [2 3 4 5 6 8 9 10 12 15 16]; assert(isequal(your_fcn_name(n),A_correct))

q = 7 q = 7 11 q = 7 11 13 q = 7 11 13 14 q = 7 11 13 14 17 r = 2 3 4 5 6 8 9 10 12 15 16

7   Pass
n = 31; A_correct = [2 3 4 5 6 8 9 10 12 15 16 18 20 24 25 27 30]; assert(isequal(your_fcn_name(n),A_correct))

q = 7 q = 7 11 q = 7 11 13 q = 7 11 13 14 q = 7 11 13 14 17 q = 7 11 13 14 17 19 q = 7 11 13 14 17 19 21 q = 7 11 13 14 17 19 21 22 q = 7 11 13 14 17 19 21 22 23 q = 7 11 13 14 17 19 21 22 23 26 q = 7 11 13 14 17 19 21 22 23 26 28 q = 7 11 13 14 17 19 21 22 23 26 28 29 q = 7 11 13 14 17 19 21 22 23 26 28 29 31 r = 2 3 4 5 6 8 9 10 12 15 16 18 20 24 25 27 30