Problem 49663. Given perimeter of a circle(P) and radius(r) find out what is the area of circle.

Created by Mahesh Patil

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<div style = "text-align: start; line-height: 20.44px; min-height: 0px; white-space: normal; color: rgb(0, 0, 0); font-family: Menlo, Monaco, Consolas, monospace; font-style: normal; font-size: 14px; font-weight: 400; text-decoration: none solid rgb(0, 0, 0); white-space: normal; "><div style="block-size: 42px; display: block; min-width: 0px; padding-block-start: 0px; padding-top: 0px; perspective-origin: 407px 21px; transform-origin: 407px 21px; vertical-align: baseline; "><div style="font-family: Helvetica, Arial, sans-serif; line-height: 21px; margin-block-end: 9px; margin-block-start: 2px; margin-bottom: 9px; margin-inline-end: 10px; margin-inline-start: 4px; margin-left: 4px; margin-right: 10px; margin-top: 2px; perspective-origin: 384px 21px; text-align: left; transform-origin: 384px 21px; white-space: pre-wrap; margin-left: 4px; margin-top: 2px; margin-bottom: 9px; margin-right: 10px; "><span style="block-size: auto; display: inline; margin-block-end: 0px; margin-block-start: 0px; margin-bottom: 0px; margin-inline-end: 0px; margin-inline-start: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px; perspective-origin: 0px 0px; transform-origin: 0px 0px; "><span style="">We ahve to find out the relation between area of circle and perimeter of circle. Then we have get area of circle in terms of perimeter of circle.</span></span></div></div></div>

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15 Solutions
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Last Solution submitted on Feb 13, 2021

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Ali ah on 31 Dec 2020

nice and simple question

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Solution 4492278

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Mahesh Patil on 29 Dec 2020

Find the relation between area of circle and perimeter of circle; get the relation and then apply it to get the answer

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Problem 49663. Given perimeter of a circle(P) and radius(r) find out what is the area of circle.

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Last 200 Solutions

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Problem Recent Solvers14

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Problem 49663. Given perimeter of a circle(P) and radius(r) find out what is the area of circle.

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Last 200 Solutions

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Problem Recent Solvers14

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More from this Author1

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