Problem 661. Spot the outlier

Solution 1015114

Submitted on 13 Oct 2016 by Hoai Tran Quoc

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2 Comments

2 Comments

Hoai Tran Quoc on 13 Oct 2016

Very interesting, why the test# 3 is not passed. It turned out that the two number
(x4-x1)*(y2-y1) is not the same as (y4-y1)*(x2-x1) due to floating point. I have to compare the subtraction with 10*eps.

Hoai Tran Quoc on 14 Oct 2016

Very interesting. I could not understand why I had not passed the test# 3. It turned out that the two number (x4-x1)*(y2-y1) and (y4-y1)*(x2-x1) are not the same due to floating point. My choice is to compare the absolute difference with 10*eps.

Test Suite

Test	Status	Code Input and Output
1	Pass	pts = [0 1; 0 2; 3 2; 0 3; 0 4 ]; outlier = 3; assert(isequal(spot_the_outlier(pts),outlier))
2	Pass	pts = [10 -1;7 0;9.5 0.3;9 1.6;8.5 2.9]; outlier = 2; assert(isequal(spot_the_outlier(pts),outlier))
3	Pass	pts = [-0.6 -6;-0.2 0;0 3;-0.8 -9;-2 1;-0.4 -3]; outlier = 5; assert(isequal(spot_the_outlier(pts),outlier))
4	Pass	pts = [2 5;0 4;0 0;4 6;-2 3]; outlier = 3; assert(isequal(spot_the_outlier(pts),outlier))
5	Pass	pts = [1 0; 0 1; 1 2; 1.5 2.5; 2 3; 3 4 ]; outlier = 1; assert(isequal(spot_the_outlier(pts),outlier))

Problem 661. Spot the outlier

Test Suite

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Problem 661. Spot the outlier

Test Suite

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