{"group":{"id":1,"name":"Community","lockable":false,"created_at":"2012-01-18T18:02:15.000Z","updated_at":"2026-04-06T14:01:22.000Z","description":"Problems submitted by members of the MATLAB Central community.","is_default":true,"created_by":161519,"badge_id":null,"featured":false,"trending":false,"solution_count_in_trending_period":0,"trending_last_calculated":"2026-04-06T00:00:00.000Z","image_id":null,"published":true,"community_created":false,"status_id":2,"is_default_group_for_player":false,"deleted_by":null,"deleted_at":null,"restored_by":null,"restored_at":null,"description_opc":null,"description_html":null,"published_at":null},"problems":[{"id":44337,"title":"Sums of Distinct Powers","description":"You will be given three numbers: base, nstart, and nend.  Write a MATLAB script that will compute the sum of a sequence of both the distinct powers of base as well as sums of distinct powers of base.  Your sequence should start with the 'nstart'th term and end with the 'nend'th term.  For example:\r\n\r\n* base=4\r\n* nstart=2\r\n* nend=6\r\n\r\nThe first several sums of the distinct powers of 4 are:\r\n\r\n* 1 (4^0)\r\n* 4 (4^1)\r\n* 5 (4^1 + 4^0)\r\n* 16 (4^2)\r\n* 17 (4^2 + 4^0)\r\n* 20 (4^2 + 4^1)\r\n* 21 (4^2 + 4^1 + 4^0)\r\n* 64 (4^3)\r\n* 65 (4^3 + 4^0)\r\n\r\nSince nstart=2 and nend=6 in this example, you take the second through the sixth terms of this sequence.  The correct output would be 4+5+16+17+20, or 62.  Notice that the number 8 does not occur in this pattern.  While 8 is a multiple of 4, 8=4^1+4^1.  Because there are two 4^1 terms in the sum, 8 does not qualify as a sum of *distinct* powers of 4.  You can assume that all three will be integers, base\u003e1, and that nstart\u003cnend.  Good luck!","description_html":"\u003cp\u003eYou will be given three numbers: base, nstart, and nend.  Write a MATLAB script that will compute the sum of a sequence of both the distinct powers of base as well as sums of distinct powers of base.  Your sequence should start with the 'nstart'th term and end with the 'nend'th term.  For example:\u003c/p\u003e\u003cul\u003e\u003cli\u003ebase=4\u003c/li\u003e\u003cli\u003enstart=2\u003c/li\u003e\u003cli\u003enend=6\u003c/li\u003e\u003c/ul\u003e\u003cp\u003eThe first several sums of the distinct powers of 4 are:\u003c/p\u003e\u003cul\u003e\u003cli\u003e1 (4^0)\u003c/li\u003e\u003cli\u003e4 (4^1)\u003c/li\u003e\u003cli\u003e5 (4^1 + 4^0)\u003c/li\u003e\u003cli\u003e16 (4^2)\u003c/li\u003e\u003cli\u003e17 (4^2 + 4^0)\u003c/li\u003e\u003cli\u003e20 (4^2 + 4^1)\u003c/li\u003e\u003cli\u003e21 (4^2 + 4^1 + 4^0)\u003c/li\u003e\u003cli\u003e64 (4^3)\u003c/li\u003e\u003cli\u003e65 (4^3 + 4^0)\u003c/li\u003e\u003c/ul\u003e\u003cp\u003eSince nstart=2 and nend=6 in this example, you take the second through the sixth terms of this sequence.  The correct output would be 4+5+16+17+20, or 62.  Notice that the number 8 does not occur in this pattern.  While 8 is a multiple of 4, 8=4^1+4^1.  Because there are two 4^1 terms in the sum, 8 does not qualify as a sum of \u003cb\u003edistinct\u003c/b\u003e powers of 4.  You can assume that all three will be integers, base\u0026gt;1, and that nstart\u0026lt;nend.  Good luck!\u003c/p\u003e","function_template":"function y = sum_distinct_powers(base,nstart,nend)\r\n  y = base*nstart*nend;\r\nend","test_suite":"%%\r\nbase=4;nstart=2;nend=6;y_correct=62;\r\nassert(isequal(sum_distinct_powers(base,nstart,nend),y_correct))\r\n%%\r\nbase=5;nstart=1;nend=1000;y_correct=1193853250;\r\nassert(isequal(sum_distinct_powers(base,nstart,nend),y_correct))\r\n%%\r\nbase=3;nstart=1;nend=1000;y_correct=14438162;\r\nassert(isequal(sum_distinct_powers(base,nstart,nend),y_correct))\r\n%%\r\nbase=3;nstart=100;nend=1000;y_correct=14397354;\r\nassert(isequal(sum_distinct_powers(base,nstart,nend),y_correct))\r\n%%\r\nbase=2;nstart=1;nend=2017;y_correct=2035153;\r\nassert(isequal(sum_distinct_powers(base,nstart,nend),y_correct))\r\n%%\r\nbase=7;nstart=1234;nend=2345;y_correct=843569026324;\r\nassert(isequal(sum_distinct_powers(base,nstart,nend),y_correct))\r\n%%\r\nbase=7;nstart=1;nend=10;y_correct=1265;\r\nassert(isequal(sum_distinct_powers(base,nstart,nend),y_correct))\r\n%%\r\nnstart=1;nend=50;\r\njunk=arrayfun(@(base) sum_distinct_powers(base,nstart,nend),2:10);\r\ny_correct=[1275 7120 26365 75000 178591 374560 714465 1266280 2116675];\r\nassert(isequal(junk,y_correct))\r\n","published":true,"deleted":false,"likes_count":6,"comments_count":9,"created_by":1615,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":156,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":35,"created_at":"2017-09-18T16:30:15.000Z","updated_at":"2026-02-03T09:26:51.000Z","published_at":"2017-10-16T01:50:59.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eYou will be given three numbers: base, nstart, and nend. Write a MATLAB script that will compute the sum of a sequence of both the distinct powers of base as well as sums of distinct powers of base. Your sequence should start with the 'nstart'th term and end with the 'nend'th term. For example:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ebase=4\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003enstart=2\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003enend=6\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe first several sums of the distinct powers of 4 are:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e1 (4^0)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e4 (4^1)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e5 (4^1 + 4^0)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e16 (4^2)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e17 (4^2 + 4^0)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e20 (4^2 + 4^1)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e21 (4^2 + 4^1 + 4^0)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e64 (4^3)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e65 (4^3 + 4^0)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eSince nstart=2 and nend=6 in this example, you take the second through the sixth terms of this sequence. The correct output would be 4+5+16+17+20, or 62. Notice that the number 8 does not occur in this pattern. While 8 is a multiple of 4, 8=4^1+4^1. Because there are two 4^1 terms in the sum, 8 does not qualify as a sum of\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003edistinct\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e powers of 4. You can assume that all three will be integers, base\u0026gt;1, and that nstart\u0026lt;nend. Good luck!\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"}],"problem_search":{"errors":[],"problems":[{"id":44337,"title":"Sums of Distinct Powers","description":"You will be given three numbers: base, nstart, and nend.  Write a MATLAB script that will compute the sum of a sequence of both the distinct powers of base as well as sums of distinct powers of base.  Your sequence should start with the 'nstart'th term and end with the 'nend'th term.  For example:\r\n\r\n* base=4\r\n* nstart=2\r\n* nend=6\r\n\r\nThe first several sums of the distinct powers of 4 are:\r\n\r\n* 1 (4^0)\r\n* 4 (4^1)\r\n* 5 (4^1 + 4^0)\r\n* 16 (4^2)\r\n* 17 (4^2 + 4^0)\r\n* 20 (4^2 + 4^1)\r\n* 21 (4^2 + 4^1 + 4^0)\r\n* 64 (4^3)\r\n* 65 (4^3 + 4^0)\r\n\r\nSince nstart=2 and nend=6 in this example, you take the second through the sixth terms of this sequence.  The correct output would be 4+5+16+17+20, or 62.  Notice that the number 8 does not occur in this pattern.  While 8 is a multiple of 4, 8=4^1+4^1.  Because there are two 4^1 terms in the sum, 8 does not qualify as a sum of *distinct* powers of 4.  You can assume that all three will be integers, base\u003e1, and that nstart\u003cnend.  Good luck!","description_html":"\u003cp\u003eYou will be given three numbers: base, nstart, and nend.  Write a MATLAB script that will compute the sum of a sequence of both the distinct powers of base as well as sums of distinct powers of base.  Your sequence should start with the 'nstart'th term and end with the 'nend'th term.  For example:\u003c/p\u003e\u003cul\u003e\u003cli\u003ebase=4\u003c/li\u003e\u003cli\u003enstart=2\u003c/li\u003e\u003cli\u003enend=6\u003c/li\u003e\u003c/ul\u003e\u003cp\u003eThe first several sums of the distinct powers of 4 are:\u003c/p\u003e\u003cul\u003e\u003cli\u003e1 (4^0)\u003c/li\u003e\u003cli\u003e4 (4^1)\u003c/li\u003e\u003cli\u003e5 (4^1 + 4^0)\u003c/li\u003e\u003cli\u003e16 (4^2)\u003c/li\u003e\u003cli\u003e17 (4^2 + 4^0)\u003c/li\u003e\u003cli\u003e20 (4^2 + 4^1)\u003c/li\u003e\u003cli\u003e21 (4^2 + 4^1 + 4^0)\u003c/li\u003e\u003cli\u003e64 (4^3)\u003c/li\u003e\u003cli\u003e65 (4^3 + 4^0)\u003c/li\u003e\u003c/ul\u003e\u003cp\u003eSince nstart=2 and nend=6 in this example, you take the second through the sixth terms of this sequence.  The correct output would be 4+5+16+17+20, or 62.  Notice that the number 8 does not occur in this pattern.  While 8 is a multiple of 4, 8=4^1+4^1.  Because there are two 4^1 terms in the sum, 8 does not qualify as a sum of \u003cb\u003edistinct\u003c/b\u003e powers of 4.  You can assume that all three will be integers, base\u0026gt;1, and that nstart\u0026lt;nend.  Good luck!\u003c/p\u003e","function_template":"function y = sum_distinct_powers(base,nstart,nend)\r\n  y = base*nstart*nend;\r\nend","test_suite":"%%\r\nbase=4;nstart=2;nend=6;y_correct=62;\r\nassert(isequal(sum_distinct_powers(base,nstart,nend),y_correct))\r\n%%\r\nbase=5;nstart=1;nend=1000;y_correct=1193853250;\r\nassert(isequal(sum_distinct_powers(base,nstart,nend),y_correct))\r\n%%\r\nbase=3;nstart=1;nend=1000;y_correct=14438162;\r\nassert(isequal(sum_distinct_powers(base,nstart,nend),y_correct))\r\n%%\r\nbase=3;nstart=100;nend=1000;y_correct=14397354;\r\nassert(isequal(sum_distinct_powers(base,nstart,nend),y_correct))\r\n%%\r\nbase=2;nstart=1;nend=2017;y_correct=2035153;\r\nassert(isequal(sum_distinct_powers(base,nstart,nend),y_correct))\r\n%%\r\nbase=7;nstart=1234;nend=2345;y_correct=843569026324;\r\nassert(isequal(sum_distinct_powers(base,nstart,nend),y_correct))\r\n%%\r\nbase=7;nstart=1;nend=10;y_correct=1265;\r\nassert(isequal(sum_distinct_powers(base,nstart,nend),y_correct))\r\n%%\r\nnstart=1;nend=50;\r\njunk=arrayfun(@(base) sum_distinct_powers(base,nstart,nend),2:10);\r\ny_correct=[1275 7120 26365 75000 178591 374560 714465 1266280 2116675];\r\nassert(isequal(junk,y_correct))\r\n","published":true,"deleted":false,"likes_count":6,"comments_count":9,"created_by":1615,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":156,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":35,"created_at":"2017-09-18T16:30:15.000Z","updated_at":"2026-02-03T09:26:51.000Z","published_at":"2017-10-16T01:50:59.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eYou will be given three numbers: base, nstart, and nend. Write a MATLAB script that will compute the sum of a sequence of both the distinct powers of base as well as sums of distinct powers of base. Your sequence should start with the 'nstart'th term and end with the 'nend'th term. For example:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ebase=4\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003enstart=2\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003enend=6\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe first several sums of the distinct powers of 4 are:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e1 (4^0)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e4 (4^1)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e5 (4^1 + 4^0)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e16 (4^2)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e17 (4^2 + 4^0)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e20 (4^2 + 4^1)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e21 (4^2 + 4^1 + 4^0)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e64 (4^3)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e65 (4^3 + 4^0)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eSince nstart=2 and nend=6 in this example, you take the second through the sixth terms of this sequence. The correct output would be 4+5+16+17+20, or 62. Notice that the number 8 does not occur in this pattern. While 8 is a multiple of 4, 8=4^1+4^1. Because there are two 4^1 terms in the sum, 8 does not qualify as a sum of\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003edistinct\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e powers of 4. You can assume that all three will be integers, base\u0026gt;1, and that nstart\u0026lt;nend. Good luck!\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"}],"term":"tag:\"distinct 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