Solution 2673695

Submitted on 9 Jul 2020 by Umur Ulas Harman

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Umur Ulas Harman on 9 Jul 2020

function A = isocelesArea(x,y)
u=(2*x+y)/2;
A = sqrt(u*(u-x)^2*(u-y));
end

Test	Status	Code Input and Output
1	Pass	x = 5; y = 8; A_correct = 12; tolerance = 1e-12; assert(abs(isocelesArea(x,y)-A_correct)<tolerance)
2	Pass	x = 2; y = 2; A_correct = sqrt(3); tolerance = 1e-12; assert(abs(isocelesArea(x,y)-A_correct)<tolerance)
3	Pass	x = 10; y = 2; A_correct = sqrt(99); tolerance = 1e-12; assert(abs(isocelesArea(x,y)-A_correct)<tolerance)

Test

Status

Code Input and Output

Pass

x = 5; y = 8; A_correct = 12; tolerance = 1e-12; assert(abs(isocelesArea(x,y)-A_correct)<tolerance)

Pass

x = 2; y = 2; A_correct = sqrt(3); tolerance = 1e-12; assert(abs(isocelesArea(x,y)-A_correct)<tolerance)

Pass

x = 10; y = 2; A_correct = sqrt(99); tolerance = 1e-12; assert(abs(isocelesArea(x,y)-A_correct)<tolerance)

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Problem 2020. Area of an Isoceles Triangle