Answered
Median gray level value
Hi Faraz, you can simply make a mask of the pixels you *don't* want to include, then take the median of all the others: Im = ...

14 years ago | 1

| accepted

Answered
Changing the font displayed in a waitbar
It's hidden a little bit: h = waitbar; titleHandle = get(findobj(h,'Type','axes'),'Title'); set(titleHandle,'FontSi...

14 years ago | 0

Answered
Comparing between Array Elements
If you were running the code you put in the question, you should have gotten an error (rather than an absurd answer). There was ...

14 years ago | 1

Answered
working with two variables
It's not the most efficient code, but I've kept things similar to your original input for clarity. Think now of "MF" as a grid o...

14 years ago | 0

| accepted

Answered
Specifying 3D points with the mouse
In short, don't use *ginput()*, use *get(ax,'CurrentPoint')* instead. Basically the current position of the mouse, combined w...

14 years ago | 1

| accepted

Answered
Re-scaling matrix entries to lie within a range
You can use the "mod" command with modulus 2*pi, then minus pi from the result. For example: mod(4.5*pi + pi, 2*pi) - pi ...

14 years ago | 0

| accepted

Answered
How to extract cell array in matlab
If you have strings of dates, use datevec as follows: [Y, M, D, H, MN, S] = datevec('22.11.2011 13:58:56.16'); You'll noti...

14 years ago | 1

Answered
How to generate a 3d Spline curve can interp3 be of help
Hi Anjani, I think this is what you want to do: Get your original data: d=[0.007773 0.649806 0.627914, 0.007773 0.652142 0...

14 years ago | 2

| accepted

Answered
Iteration in Matlab
Your "break" command only breaks out of one loop. Instead try: exitLoop = false; C_pd = Specific_Heat(T_d,X_d); ...

14 years ago | 0

| accepted

Answered
Interpolating Data from Vectors of Different Length
This is a job for the *interp1* function: % Make original data oldPcntVals = [0 .1 .3 .7 .9 1]; oldYvals = [10 12 15 13 ...

14 years ago | 1

| accepted

Answered
Reversing Columns in a Matrix
Use *fliplr* to flip a matrix left-to-right: a = [1 2 3 4 5 6] b = [a(1) fliplr(a(2:5)) a(6)] See also: *flipud* (fli...

14 years ago | 0

| accepted

Answered
prolem in sparse
Huda, try this (edited to update with comments): % Make Data x=sparse(10,10); x(1:10,1:10)=5; % Get the rows, cols, ...

14 years ago | 0

| accepted

Answered
Variable for range in xlswrite
Providing a variable as a string should be exactly the same as providing that string directly. Here are 3 possibilities that I c...

14 years ago | 0

| accepted

Answered
The problem with the function 'all'
I think you want to compare a(1,:) to b, and a(2,:) to b. So try this using bsxfun: all(bsxfun(@gt, a, b),2) Does that give ...

14 years ago | 1

| accepted

Answered
What is your MATLAB uptime
I've got 2 machines with MATLAB always open :) PC1. The desktop - hack around developing and testing. PC2. The runner - An...

14 years ago | 0

Answered
plot different color
Steven, try this, it plots two separate plots depending on whether y is above/below 0.5: x = 0:pi/20:10*pi; y = sin(x); mas...

14 years ago | 1

Answered
how to format rows columns for display
Hi FIR, Make data: D = [(1:800)' randi(4,800,1) rand(800,1)+99]; Display all data rounded: disp(round(D)) D...

14 years ago | 0

| accepted

Answered
function
Baba, variables created *inside* a function are _limited_ to that function's scope. If you want to have DATA available outside t...

14 years ago | 1

| accepted

Answered
error in selecting data
Hi FIR, The error comes because the ismember() function expects *either* a matrix of numbers *or* a cell array of strings. Sinc...

14 years ago | 0

| accepted

Answered
How to count changes in binary transmission through channel
Hmmm... does this answer your question, Will? originalBits = rand(1,100000)>0.5; returnedBits = transmitSignal(originalBits...

14 years ago | 0

Answered
Binary Number Transmitter
The "if" statement is only executed once, however you have 100000 elements. Essentially, if *any* elements in a vector are false...

14 years ago | 0

| accepted

Answered
question about structures in Matlab
Yes, that's possible: s = struct('field1', 45, 'field2', 'Nothing') s.field3 = struct('subfield1', 232) And you can acc...

14 years ago | 0

| accepted

Answered
sorting 3d matrix by value of a cell
Hi Markus, If you have a 3D *MATRIX* of numbers, and the distance you want to sort by is stored, say, in the (1,1) location of ...

14 years ago | 1

Answered
basics - a more compact way to do this...?
The simplest method is: k = size(x, 2) The second argument of the "size" method is the dimension in which to query - in your...

14 years ago | 0

| accepted

Answered
Help needed in debugging the code for Identifying round objects ..
This is a pretty good attempt, and I think the code below does what you intended. The one biggest change is that instead of try...

14 years ago | 1

| accepted

Answered
Creating matrix from a for loop
Hi athpapa, I don't know what your "A" matrix or "symbols" matrix had, so I will just make them random numbers: A = randi(50...

14 years ago | 0

| accepted

Answered
How to specifically select columns in a data matrix?
Try: xdatatemp = xdata(:,[77:83 86]) And you can even use "end" keywords such as: xdatatemp = xdata(:,[77:83 86 end end:...

14 years ago | 41

| accepted

Answered
concatenating / manipulating matrix based on user input
Hi Karan, try this: The setup: matrix_dates = [ 1 1701 1 1702 4955 2 ...

14 years ago | 0

| accepted

Answered
combination
Mohammad, try this for a solution. It is a loop that iterates along the columns of x, picking the next available x(row,col). Whe...

14 years ago | 0

Answered
Extracting Cracks
Hi Ratna, It's quite difficult due to the relative intensities - cracks are only a "little" bit lighter than solid material. Her...

14 years ago | 1

| accepted

Load more