gfsub

Subtract polynomials over Galois field

Syntax

c = gfsub(a,b,p) c = gfsub(a,b,p,len) c = gfsub(a,b,field)

Description

Note

This function performs computations in GF(p^m), where p is prime. To work in GF(2^m), apply the - operator to Galois arrays of equal size. For details, see Example: Addition and Subtraction.

c = gfsub(a,b,p) calculates a minus b, where a and b represent polynomials over GF(p) and p is a prime number. a, b, and c are row vectors that give the coefficients of the corresponding polynomials in order of ascending powers. Each coefficient is between 0 and p-1. If a and b are matrices of the same size, the function treats each row independently. Alternatively, a and b can be represented as polynomial character vectors.

c = gfsub(a,b,p,len) subtracts row vectors as in the syntax above, except that it returns a row vector of length len. The output c is a truncated or extended representation of the answer. If the row vector corresponding to the answer has fewer than len entries (including zeros), extra zeros are added at the end; if it has more than len entries, entries from the end are removed.

c = gfsub(a,b,field) calculates a minus b, where a and b are the exponential format of two elements of GF(p^m), relative to some primitive element of GF(p^m). p is a prime number and m is a positive integer. field is the matrix listing all elements of GF(p^m), arranged relative to the same primitive element. c is the exponential format of the answer, relative to the same primitive element. See Representing Elements of Galois Fields for an explanation of these formats. If a and b are matrices of the same size, the function treats each element independently.

Examples

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Subtract Two GF Arrays

Open Live Script

Calculate $(2 + 3 x + x^{2}) - (4 + 2 x + 3 x^{2})$ over GF(5).

x = gfsub([2 3 1],[4 2 3],5)

x = 1×3

     3     1     3

Subtract the two polynomials and display the first two elements.

y = gfsub([2 3 1],[4 2 3],5,2)

y = 1×2

     3     1

For prime number p and exponent m, create a matrix listing all elements of GF(p^m) given primitive polynomial $2 + 2 x + x^{2}$ .

p = 3;
m = 2;
primpoly = [2 2 1];
field = gftuple((-1:p^m-2)',primpoly,p);

Subtract $A^{4}$ from $A^{2}$ . The result is $A^{7}$ .

g = gfsub(2,4,field)

g = 
7

Version History

Introduced before R2006a