Exact Image extraction is not possible

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I want to extract the inner black portion of image CT14.jpg using mask.png as a mask by multiplying these two image but every time I get the outer portion of the image. How it is possible to segment these two inner lung portion. please help me.

Accepted Answer

Image Analyst
Image Analyst on 8 Dec 2013
Try this:
clc; % Clear the command window.
close all; % Close all figures (except those of imtool.)
imtool close all; % Close all imtool figures if you have the Image Processing Toolbox.
clear; % Erase all existing variables. Or clearvars if you want.
workspace; % Make sure the workspace panel is showing.
format long g;
format compact;
fontSize = 20;
% Check that user has the Image Processing Toolbox installed.
hasIPT = license('test', 'image_toolbox');
if ~hasIPT
% User does not have the toolbox installed.
message = sprintf('Sorry, but you do not seem to have the Image Processing Toolbox.\nDo you want to try to continue anyway?');
reply = questdlg(message, 'Toolbox missing', 'Yes', 'No', 'Yes');
if strcmpi(reply, 'No')
% User said No, so exit.
return;
end
end
% Read in gray scale demo image.
folder = 'C:\Users\jhilam\Documents\Temporary';
baseFileName = 'CT14.jpg';
% Get the full filename, with path prepended.
fullFileName = fullfile(folder, baseFileName);
% Check if file exists.
if ~exist(fullFileName, 'file')
% File doesn't exist -- didn't find it there. Check the search path for it.
fullFileName = baseFileName; % No path this time.
if ~exist(fullFileName, 'file')
% Still didn't find it. Alert user.
errorMessage = sprintf('Error: %s does not exist in the search path folders.', fullFileName);
uiwait(warndlg(errorMessage));
return;
end
end
grayImage = imread(fullFileName);
% Get the dimensions of the image.
% numberOfColorBands should be = 1.
[rows, columns, numberOfColorBands] = size(grayImage);
if numberOfColorBands > 1
% It's not really gray scale like we expected - it's color.
% Convert it to gray scale by taking only the green channel.
grayImage = grayImage(:, :, 2); % Take green channel.
end
% Display the original gray scale image.
subplot(2, 3, 1);
imshow(grayImage, []);
title('Original Grayscale Image', 'FontSize', fontSize);
% Enlarge figure to full screen.
set(gcf, 'Units', 'Normalized', 'OuterPosition', [0 0 1 1]);
% Give a name to the title bar.
set(gcf, 'Name', 'Demo by ImageAnalyst', 'NumberTitle', 'Off')
% Blacken the white bar artifact in the left 5 columns.
grayImage(:, 1:5) = 0;
% Let's compute and display the histogram.
[pixelCount, grayLevels] = imhist(grayImage);
subplot(2, 3, 2);
bar(grayLevels, pixelCount);
grid on;
title('Histogram of original image', 'FontSize', fontSize);
xlim([0 grayLevels(end)]); % Scale x axis manually.
% Binarize the image to get the body.
binaryImage = grayImage > 150;
% Display the binary image.
subplot(2, 3, 3);
imshow(binaryImage, []);
title('Binary Image', 'FontSize', fontSize);
% Fill and get rid of small objects
binaryImage2 = imfill(binaryImage, 'holes');
minAcceptableSize = round(rows*columns*0.05);
binaryImage2 = bwareaopen(binaryImage2, minAcceptableSize);
% Display the binary image.
subplot(2, 3, 4);
imshow(binaryImage2, []);
title('Binary Image 2', 'FontSize', fontSize);
% Invert and OR
binaryImage2 = ~(~binaryImage2 | binaryImage);
% Display the binary image.
subplot(2, 3, 5);
imshow(binaryImage2, []);
axis on;
title('Binary Image 2', 'FontSize', fontSize);
% Fill again
binaryImage3 = imfill(binaryImage2, 'holes');
% Get rid of small things again.
binaryImage3 = bwareaopen(binaryImage3, minAcceptableSize);
% And it with binary image 2
binaryImage3 = binaryImage3 & binaryImage2;
% Display the binary image.
subplot(2, 3, 6);
imshow(binaryImage3, []);
title('Binary Image 3', 'FontSize', fontSize);
uiwait(helpdlg('Done with Demo by Image Analyst!'));

More Answers (2)

Image Analyst
Image Analyst on 6 Dec 2013
How did you get that mask? Why not get one that is not connected to the outer black stuff? Anyway to mask the gray image by a binary (logical) image, you can do it in two ways.
maskedImage = grayImage; % Initialize
maskedImage(~mask) = 0;
or
maskedImage = grayImage .* uint8(mask); % or uint16, whatever grayImage is.
  1 Comment
Image Analyst
Image Analyst on 8 Dec 2013
That's because the Otsu method is lousy. It rarely picks good thresholds for real world images unless they're very contrasty with a bimodal histogram.

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Jhilam Mukherjee
Jhilam Mukherjee on 8 Dec 2013
At first the Otsu's thresholding technique is applied on the second image, which give a binary thresholded image, then an= morphological operation performed over thresholded image that yielded the first image.
I get output the above image but my desired out put is
in gray scale format. but I can't obtained this output. In each images I found the above image. How is it possible

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