Rearrange 3 small matrices to a bigger one with a certain order: taking first n-rows of each of the smaller matrices after each other

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I have three smaller Matrices that I want to transform to one bigger one with the following order:
>> A1 =
1 1
2 2
3 3
4 4
A2 =
5 5
6 6
7 7
8 8
A3 =
9 9
10 10
11 11
12 12
They should be transformed to one Matrix in this order:
B =
1 1
2 2
5 5
6 6
9 9
10 10
3 3
4 4
7 7
8 8
11 11
12 12
So always take the first n-rows of each matrix (here n=2, in the actual case 'n' ist way higher), then take all the second "packages" and so on (In this case: Take first two lines of each Matrix, then take lines 3-4 of each matrix, then lines 5-6 of each matrix and so on)
Is there a nice and quick solution that does not require loops? Maybe using reshape or some functions to swap lines or using indices or so..?
Thanks in advance again!

Accepted Answer

Azzi Abdelmalek
Azzi Abdelmalek on 3 Jan 2014
Edited: Azzi Abdelmalek on 3 Jan 2014
m=size(A1,2);
n=2
A11=permute(reshape(A1',m,n,[]),[2 1 3]);
A22=permute(reshape(A2',m,n,[]),[2 1 3]);
A33=permute(reshape(A3',m,n,[]),[2 1 3]);
A=permute([A11;A22;A33],[2 1 3]);
B=A(:,:)'

More Answers (2)

Andrei Bobrov
Andrei Bobrov on 6 Jan 2014
Edited: Andrei Bobrov on 6 Jan 2014
a1 = cat(1,A1,A2,A3);
t = rem(0:size(a1,1)-1,4)+1 <= 2;
out = [a1(t,:);a1(~t,:)];
or in one row
out = reshape(permute(reshape(cat(1,A1,A2,A3),2,2,3,[]),[1 3 2 4]),[],2);

Jos (10584)
Jos (10584) on 6 Jan 2014
You can use some clever indexing:
A1 = cumsum(ones(4,2)), A2 = A1 + 4, A3 = A1 + 8 % as above
n = 2 ;
% engine
m = size(A1,1) ; % all the same
% build a clever sorting matrix IX
IX = repmat([1+floor((0:m-1)/n) ; zeros(1,m) ; 1:m].', 3, 1)
IX(:,2) = 1+floor((0:(3*m)-1)/m)
% col 1 : selection order based on n
% col 2 : which matrix (A1, A2 or A3),
% col 3 : which element inside matrix
% sort them nicely
[IXsorted,SI] = sortrows(IX)
B = [A1 ; A2 ; A3]
B = B(SI,:)

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