How to loop through a dataset and skip every other row?

I have a dataset and would like to create a loop to skip every other row and get the data pertaining to that data. for example:
  • A 1,2,3,4,5,6
  • B 7,8,9,10,11,12
  • C 13,14,15,16,17,18
I would like to write a for loop to get the data in rows A,C, E, G, etc.

Answers (2)

If M is your matrix
out=M(1:2:end,:)

10 Comments

is there a way to choose a specific row to start for example lets say I wanted to start from row B and have it print B,D,F, etc
the data contains subsets for example a1, a2, a3, a4, a5...a24, b1, b2, b3....b24, etc
how can I just print the following rows: a2, a4, a6, a8....o24 b1,b3,b5,b7,b9....p23 b2,b4,b6,b8....p24
If you mean, for example
data=[1 2 3 4 5 6 7 8 9 10]
out=data(2:2:end)
It's just like I said above
Maybe this will clarify my question:
The code that you gave me works and I just need to be able to get rid of the ones that ends in for example A(3,5,7,9,11,13,15,17,19,21,23...
outcome should be (1,A2)(1,C2)(1,E2)(1,G2)(1,I2)(1,K2)(1,M2)(1,O2), (1,A4)...etc...
There is no, in Matlab, data like
(1,A2)(1,C2)(1,E2)(1,G2)(1,I2)(1,K2)(1,M2)(1,O2), (1,A4).
What class of data are using?
these were imported and represent a location.
Those are strings. Are they stored in a cell array?
they are stored in data9.Location
That's the variable name. What's the variable type? Most likely a cell array. You can find out by:
class(data9.Location)

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If you indeed have a cell array of strings, this should work:
your_data = cellfun(@(x) x(3:end),data9.Location,'uniformoutput',false)
Please accept an answer if it helps you.

2 Comments

is there a way to sort the column so that all the A's, are together?
That's a different question.
sort(your_data)
Please accept an answer if it helps you.

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Asked:

on 13 Jan 2014

Commented:

on 14 Jan 2014

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