Create two vectors X and Y of values from (-pi) to pi with a spacing of pi/10. Define the vector Z as: Z = (sin(sqrt(​x^2+y^2)))​/(sqrt(x^2​+y^2))

Im trying to plot function. I have wrote x=[-pi:pi/10:pi] and y=[-pi:pi/10:pi]. Also Z = (sin(sqrt(x.^2+y.^2)))/(sqrt(x.^2+y.^2)). When I try to plot the function z somehow gets to be only one number such as -0.0227 and I get error 'Vectors must be the same lengths'. Please help me to get this problem right

Answer 1

[Roger Stafford]

You need to put a "dot" in your division operator:

Z = (sin(sqrt(x.^2+y.^2)))./(sqrt(x.^2+y.^2))

What you had there without the dot was matrix division which in this case produces a single scalar.

I am curious though as to what you are trying to do. Both the x and y vectors are identical. It looks as though you were attempting to accomplish something other than what you produced in the code. If so, please tell what that is.

[Lisa]

Thanks a lot! It did work this time=))

Answer 2

[Lisa]

Im trying to plot in mesh and surf same problem above. Im writing plot3(x,z,y,z); subplot(2,2,1) mesh(x,z,y,z) title('Mesh Plot'),xlable('x-axis'),ylable('y-axis'),zlable('z-axis') I would have to make three different shading scheme as well, so if you could help me that would be awesome!

Answer 3

[Marta Salas]

[x,y] = meshgrid(-pi:pi/10:pi)
z = (sin(sqrt(x.^2+y.^2)))./(sqrt(x.^2+y.^2))
mesh(x,y,z)

[Lisa]

Thanks!