I didn't understand the output of "y=sin(2*pi*t)" where t=[1 2 3 4 5].

output is 1.0e-14 *

   -0.0245   -0.0490   -0.0735   -0.0980   -0.1225
i think ouput should be 0 0 0 0 0 because sin(multiple of 2*pi) is always zero.
plz help.

Answer 1

[Azzi Abdelmalek]

2*pi is not stored exactly as 2*pi, but stored with some error

[Anurag]

I didn't get you..can you please explain.

[Azzi Abdelmalek]

each number, in Matlab or other language is stored with a certain precision, you can not store pi with an infinity of decimals. Look at

http://www.mathworks.com/help/matlab/matlab_prog/floating-point-numbers.html