How to create a continuos surface in 3D

Hi, I have this .mat file that is a 8950x3 matrix, the 1st column contains the x-coordinates, the 2nd one the y-coordinates and the third contains the z-coordinates. I would draw a continuos surface like the following figure

The only difference is that z is not the result of a function but is a vector. Is it possible? Thanks to all!

Answer 1

[Mischa Kim]

How about doing it from scratch?

 x = -2:0.1:2;
 y = -2:0.1:2;
 [X,Y] = meshgrid(x,y);
 Z = X.*exp(-(X - Y.^2).^2 - Y.^2);
 surf(X,Y,Z)

[Francesco]

But isn't it the script used to generate the example figure?

[Mischa Kim]

Yes it is. If you want to generate directly from the matrix from the .mat file, this should work:

 M  = sortrows(m,[1 2])   % m is the matrix from the .mat file
 nc = numel(unique(M(:,1)));
 x  = reshape(M(:,1),[],nc);
 y  = reshape(M(:,2),[],nc);
 z  = reshape(M(:,3),[],nc);
 surf(x,y,z)

[Francesco]

It works very well! Thank you!

Answer 2

[Youssef Khmou]

Try to use this method :

 % X is the 8950*3 matrix
 x=X(:,1)'*X(:,1); % 8950x8950
 y=X(:,2)'*X(:,2);
 z=X(:,3)'*X(:,3);
 figure; surf(X,Y,Z)

[Francesco]

I tried to do like you suggested but I have this error: Error using surf (line 75) Z must be a matrix, not a scalar or vector

[Francesco]

I noticed right now that no one among x y and z are matrices but scalar value

[Youssef Khmou]

use :

X=X';

and perform the code above