why when i make conv between an averaging filter and a noisy circuit it doesn't get filtered?
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n=0:499
x=sin(2*pi*n/50)
y=x+0.1*randn(size(n))
h=[11111]/5
z=conv(h,y)
1 Comment
amira ramadan
on 29 Apr 2014
Accepted Answer
More Answers (1)
Andrei Bobrov
on 29 Apr 2014
Edited: Andrei Bobrov
on 29 Apr 2014
n=0:499;
x=sin(2*pi*n/50);
y=x+0.1*randn(size(n));
h=[1,1,1,1,1]/5;
z=conv(y,h,'same');
3 Comments
amira ramadan
on 29 Apr 2014
Andrei Bobrov
on 29 Apr 2014
corrected
amira ramadan
on 3 May 2014
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