How to generate an array alternating the values of two others?

So, I have two arrays (I made them simple for the example)

A = [1 2 3 4 5 6]; B = [10 20 30 40 50 60 70 80 90 100 110 120 130 140 150];

The array I wish to generate is [1 10 2 20 3 30 4 40 5 50 6 60 1 70 2 80 3 90 ...]

Any idea of how to proceed? For now, I'm trying on something like this:

Sequence = []; for i = 1: length(B) j=% ??? range 1:length(A) i=1 j=1; ... i=7 j=1; i=8 j=2; ... 1=n j=??? Sequence = [Sequence A(1,j)]; Sequence = [Sequence B(1,i)]; end

Answer 1

[Jos (10584)]

A = [1 2 3 4 5 6]; 
B = [10 20 30 40 50 60 70 80 90 100 110 120 130 140 150];

% in steps
N = max(numel(A),numel(B))
ia = 1+rem(0:N-1, numel(A)) 
ib = 1+rem(0:N-1, numel(B))
C = [A(ia) ; B(ib)]
C = reshape(C,1,[]) 

% in a one-liner
C2 = reshape([A(1+rem(0:max(numel(A),numel(B))-1, numel(A))) ; B(1+rem(0:max(numel(A),numel(B))-1, numel(B)))],1,[])

[Andrei Bobrov]

+1

Answer 2

[George Papazafeiropoulos]

A = [1 2 3 4 5 6];

B = [10 20 30 40 50 60 70 80 90 100 110 120 130 140 150];

M1=[A,A,A(1:3)];

M2=B;

M=[M1;M2];

Sequence=M(:)'

Answer 3

[Andrei Bobrov]

out0 = [A(rem(0:numel(B)-1,numel(A))+1);B];
out = out0(:)';