How do I add a value in ONE element of a matrix in a for loop?

Hello, let's say I have a matrix A = [1+x,1;2,5] so I want to have x to go from -20 to 20 with x~=0

then I would need to have A(i) matrices with i=40 . How do I do this on Matlab? I've been reading on internet on indexing and things like that, but I keep getting errors. I really appreciate you taking the time.

Sincerely,

[Mahdi]

Does the second row (2,5) get repeated every time? Or does it become, let's say (you have 1 to 3)

A=[1, 1;
2,1;
3,1;
2,5]

Can you show an example of what you want the output to be?

[Salar]

Sure, let's say A = [1+x,1;2,5] , and for simplicity let's have x goes from -2 to 2 with and increment of one and x~=0, so output will look like =

A_1=[-1,1;2,5]

A_2=[0,1;2,5]

A_3=[2,1;2,5]

A_4=[3,1;2,5]

Answer 1

[Image Analyst]

I show you two different methods in the loop below:

counter = 1;
A3D = [];
for x = -20 : 20
  if x == 0
    continue;
  end
  % Method #1: Load into a cell array.
  caA{counter} = [1+x,1;2,5];
  % Method #2: Load into a 3D regular, normal array
  A3D = cat(3, A3D, [1+x,1;2,5]);
  counter = counter + 1;
end
% Print to command window
celldisp(caA)
A3D

Finally I refer you to the FAQ http://matlab.wikia.com/wiki/FAQ#How_can_I_create_variables_A1.2C_A2.2C....2CA10_in_a_loop.3F

[Salar]

Thank you!!!!

Answer 2

[sst]

This should not require a for loop:

x = [-20:-1, 1:20].';
Amatrices = arrayfun(@(X) [1+X, 1; 2, 5], x, 'UniformOutput', false);

[Salar]

That works, but do you know how to do it by a for loop?